Y = x + 1....so we sub in x + 1 for y in the other equation
2x + y = 7
2x + x + 1 = 7 ....combine like terms
3x + 1 = 7....subtract 1 from both sides
3x = 7 - 1
3x = 6 ....divide both sides by 3
x = 6/3
x = 2
y = x + 1
y = 2 + 1
y = 3
so ur solution is : (2,3)
It’s in the picture , i hope this helped you
Answer:

Step-by-step explanation:
So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.
First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:

Plug -2 for one of the slopes.

Divide by -2 to find the slope of our line.

Thus, our line needs to have a slope of 1/2.
Now, let's use the point-slope form. The point-slope form is given by:

Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:

Simplify and distribute:

Subtract 4 from both sides:

The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.
Is there a photo? Or anything
Answer:
The answer is below
Step-by-step explanation:
Two triangles are said to be congruent if all the three angles and three sides of one triangle is equal to the three sides and three angles of the other triangle.
Statement Reason
RS ⊥ TS and RV ⊥ TV Given
∠S = ∠V are right angles Definition of perpendicular. Since RS ⊥ TS,
hence ∠S = 90° and RV ⊥ TV hence ∠V = 90°
ST ≅ VT Given
RT ≅ RT Reflexive property of congruence
ΔTSR ≅ ΔTVR Hypotenuse leg congruence theorem. For
two right triangles, if the hypotenuse and leg
of one triangle is the same as the hypotenuse
and leg of the second triangle, then the two
triangles are congruent.
RS ≅ RV Definition of congruency.