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jarptica [38.1K]
3 years ago
13

2x^2+3x+5=0 what are all the complex solutions?please i need help!!!

Mathematics
2 answers:
blagie [28]3 years ago
7 0
2x^2+3x+5=0

Step 1: Use quadratic formula with a=2, b=3, c=5 ^^ than do ^^

There is no real solutions I'm pretty sure!

Hope this helped!!

vesna_86 [32]3 years ago
4 0
You'll want to use the quadratic formula:

-b (+/-) sqrt(b^2 - 4ac), all divided by 2a.

Under the square root you'll get:

-11

remember that the square root of -1 is i.

sqrt(-11) can be factored to sqrt(11*-1) and then sqrt(-1) * sqrt(11)

which becomes i*sqrt(11)

so your complex solution is:

-3 (+/-) (i*sqrt(11)), all over 4
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24 written as a percentage
Yanka [14]
Any number is equal to that number over 1

So x is equal to x/1

Same thing with 24. 24 = 24/1

To get it into percent we multiply by 100 so:

\sf{\frac{24}{1}=\frac{24\times100}{1\times100}}

And simplifying that we get

\sf{\frac{2400}{100}}

And x/100 = x%

so 2400/100 = 2400% 

So your answer is <em><u>2400%</u></em> :)
5 0
4 years ago
Solve<br> plz -4p-2r-15p
IrinaVladis [17]

Answer:

-2r-19p

Step-by-step explanation:

-4p-2r-15p

add like terms

-2r-19p

3 0
3 years ago
How many half-cubes are needed to fill in the gap of the box shown? O 4 half-cubes O 8 half-cubes O 12 half-cubes O 16 half-cube
o-na [289]

Answer:

8 half cubes

Step-by-step explanation:

8 half cubes

6 0
3 years ago
Read 2 more answers
Please helpppppp!!!!
chubhunter [2.5K]

Answer:

A. -34.5>x

Step-by-step explanation:

The area is shaded below -34.5, so we know that x has to be less

6 0
3 years ago
Let L be the line parametrized by x = 2 + 2t, y = 3t, z = −1 − t. (a) Find a linear equation for the plane that is perpendicular
Elden [556K]

Answer:

Step-by-step explanation:

Given that L is a line parametrized by

x = 2 + 2t, y = 3t, z = −1 − t

The plane perpendicular to the line will have normal as this line and hence direction ratios of normal would be coefficient of t in x,y,z

i.e. (2,3,-1)

So equation of the plane would be of the form

2x+3y-z =K

Use the fact that the plane passes through (2,0,-1) and hence this point will satisfy this equation.

2(2)+3(0)-(-1) =K\\K =5

So equation is

2x+3y-z =5

b) Substitute general point of L in the plane to find the intersecting point

2(2+2t)+3t-(-1-t) =5\\4+8t+1=5\\8t=0\\t=0\\(x,y,z) = (2,0,-1)

i.e. same point given.

3 0
3 years ago
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