2x^2+3x+5=0
what are all the complex solutions?please i need help!!!
2 answers:
2x^2+3x+5=0
Step 1: Use quadratic formula with a=2, b=3, c=5 ^^ than do ^^
There is no real solutions I'm pretty sure!
Hope this helped!!
You'll want to use the quadratic formula:
-b (+/-) sqrt(b^2 - 4ac), all divided by 2a.
Under the square root you'll get:
-11
remember that the square root of -1 is i.
sqrt(-11) can be factored to sqrt(11*-1) and then sqrt(-1) * sqrt(11)
which becomes i*sqrt(11)
so your complex solution is:
-3 (+/-) (i*sqrt(11)), all over 4
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