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sp2606 [1]
3 years ago
14

4. A team of scientists is digging for fossils. The

Mathematics
1 answer:
STALIN [3.7K]3 years ago
6 0

If it's not 6 cubic feet (because by the wording the answer is given).

If one dimension of the amount of soil they remove is 6, then you have to do 6*6*6= 216

If the total amount of soil removed is 6 cubic feet, then the dimensions of the cube would be \sqrt[3]{6}

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It's geometry, not really sure what to do
Grace [21]

Answer:

K'= (-1,-1)

J'= (-1,-5)

L'= (0,-3)

Step-by-step explanation:

What you do here is, input the (x,y) coordinates into the translation.

For example, the original point K is (-3,5). Insert this into the translation.

(-3,5) → (-3+2, 5-8) = (-1,-3)

Repeat this for the next coordinates of L and J.

J= (-3,3)

(-3,3) → (-3+2, 3-8) = (-1,-5)

L= (-2, 5)

(-2, 5) → (-2+2, 5-8) = (0,-3)

5 0
3 years ago
Find the slope of the line passing through the points (8,-6) and (1, -2).​
Alik [6]

Step-by-step explanation:

The slope of the line is -4/7.

3 0
3 years ago
Read 2 more answers
Again with this please​
ElenaW [278]

Answer:

a) A dozen= 24

3 dozen= 24 x 3

= 72

b) 1 dozen= 12 bananas

A dozen cost= 24

So, 1 banana cost= 24/12

= 2

So, 6 bananas would be 2 x 6 = 12

c) 1 dozen= 12 bananas

A dozen cost= 24

1 banana cost= 24/12

= 2

d) I need to know how many people are there in your class so please mention that first :)

Mark me brainliest pleaseee

5 0
2 years ago
An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with
AleksandrR [38]

Answer:

U₂₁ and U₂₂ fits in the line of upper triangular

Step-by-step explanation:

As explain in the question

An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with all zeros above its diagonal.

(as shown in the attached image)

(a)for all 3×3 upper triangular matirices U, verify that U2 is also upper triangular

for a matrices U (having a 3*3 matrix), assuming for example, U is given below:

U = \left[\begin{array}{ccc}1&2&3\\0&5&6\\0&0&9\end{array}\right]

the element in the upper triangular are 1,2,3,5,6,9 (U₁₁, U₁₂, U₁₃; , U₂₂, U₂₃, U₂₂)

while lower triangular are 0,0,0, the element in the lower triangular are (U₂₁, U₃₁,U₃₂)

U₂₁ and U₂₂ fits in the line of upper triangular

8 0
3 years ago
PLEASE HELP ME IM STRUGGLING!!!
Kitty [74]

Answer:

The required answer is c=7\sqrt{3}

Therefore the number in green box should be 7.

Step-by-step explanation:

Given:

AB = 7√2

AD = a , BD = b , DC = c , AC = d

∠B = 45°, ∠C = 30°

To Find:

c = ?

Solution:

In Right Angle Triangle ABD Sine identity we have

\sin B = \dfrac{\textrm{side opposite to angle B}}{Hypotenuse}\\

Substituting the values we get

\sin 45 = \dfrac{AD}{AB}= \dfrac{a}{7\sqrt{2}}

\dfrac{1}{\sqrt{2}}= \dfrac{a}{7\sqrt{2}}\\\\\therefore a=7

Now in Triangle ADC Tangent identity we have

\tan C = \dfrac{\textrm{side opposite to angle C}}{\textrm{side adjacent to angle C}}

Substituting the values we get

\tan 30 = \dfrac{AD}{DC}= \dfrac{a}{c}\\\\\dfrac{1}{\sqrt{3}}=\dfrac{7}{c}\\\\\therefore c=7\sqrt{3}

The required answer is c=7\sqrt{3}

8 0
3 years ago
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