2 over 5 divided by 5 over 9

Susan had 8/9 acres of land. She planted 2/5 of it with corn. How many acres did she plant with corn?

Sergio039 [100]

$\bf \textit{how much is }\frac{2}{5}\textit{ of }\frac{8}{9}?\implies \cfrac{8}{9}\cdot \cfrac{2}{5}\implies \cfrac{16}{45}$

that's how many acres she planted with corn.

6 0

3 years ago

If x= 6 is the only x-intercept of the graph of a quadratic equation, which statement best describes the discriminant of the

denpristay [2]

Answer:

discriminant is zero (0)

Step-by-step explanation:

Actually, you have a double root here: {6, 6}: "two real, equal roots." That tells us immediately that the value of the discriminant was zero (0).

3 0

2 years ago

Read 2 more answers

. If her allowance had stayed the same, $9.00 a month, how many carnival tickets could she bu

jarptica [38.1K]

Answer:

a) number of tickets she could buy in a month with her allowance in 2008 = 4 tickets

b) number of tickets she could buy in a month with the same allowance in 2012 = 2 tickets

c) $5, an increase of 55.56%

d) $2, a 100% increase.

e) Hallie was able to buy more tickets in 2008 than in 2012.

f) $16

Step-by-step explanation:

The complete question is presented in the attached image to this answer.

a) Halie's allowance monthly = $9

Price of a ticket in 2008 = $2

number of tickets she could buy in a month with her allowance = (9/2) = 4.5 = 4 tickets (since there are no half tickets)

b) Halie's allowance monthly = $9

Price of a ticket in 2012 = $4

number of tickets she could buy in a month with her allowance = (9/4) = 2.25 = 2 tickets (since there are no quarter tickets)

c) In 2012, Hallie's allowance was $14.00 per month. How much did her monthly allowance increase between 2008 and 2012?

Her monthly allowance in 2008 = $9

Her monthly allowance in 2012 = $14

The increase = new allowance - old allowance = 14 - 9 = $5

In percentage terms,

% increase = 100% × (new - old)/(old)

% increase = 100% × (14 - 9)/9 = 55.56%

d) How much more did a carnival ticket cost in 2012 than it did in 2008?

Price of a ticket on 2008 = $2

Price of a ticket in 2012 = $4

Increase in price = 4 - 2 = $2

% increase = 100% × (4 - 2)/2 = 100%

e) Was Hallie able to buy more carnival tickets in 2008 or in 2012 with one month's allowance?

Hallie was able to buy more tickets in 2008 than in 2012.

f) What would Hallie's allowance need to be in 2012 in order for her to be able to buy as many carnival tickets as she could in 2008?

Hallie could buy 4 tickets in 2008.

Price of a ticket in 2012 = $4.

Price of 4 tickets in 2012 = 4 × $4 = $16

Hope this Helps!!!!

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cfrak%7B%20%5Corange%7B%20Question%7D%7D" id="TexFormula1" title=" \large\frak{ \

SVEN [57.7K]

Answer:

$\boxed{\sf distance \: between \: the \: objects \: \: is \: 2.5 \: cm}$

Step-by-step explanation:

According to universal law of gravitation every object in the universe attracts every other particles that surrounds it with a force which is inversely proportional to the square of their distance of separation & directly proportional to

the product of their masses, given by standard formula.

$A = G \cdot \frac{m_1.m_2}{ {d}^{2} }$

where A,d & G are force of attraction, distance of separation & proportionality constant respectively.

Given:

A1 = 2 units

d1= 5 cm

A2 = 8 units

To find:

Distance of separation when the force of attraction is 8 units d2 = ?

Solution:

Substituting the given values in above at each point,

$A_1 = G \cdot \frac{m_1.m_2}{ {d_1}^{2} } \\ 2 = G \cdot \frac{m_1.m_2}{ {5}^{2} } \\ \sf similarly \: at \: second \: point \: of \: attraction \\ A_2 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ 8 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ \sf \: \: dividing \: both \: of \: the \: equation \\ \frac{2}{8} = \frac{G \cdot \frac{m_1.m_2}{ {5}^{2} }}{G \cdot \frac{m_1.m_2}{ {d_2}^{2} } } \\ \sf \: G \: m_1 and \: m_2 \: are \: \: constant \: hence \\ \sf they \: can \: be \: cancelled \: out \\ \frac{2}{8} = \frac{ \frac{1}{ {5}^{2} } }{ \frac{1}{ {d_2}^{2} } } \\ \sf rearranging \: above \: equation \\ \frac{1}{4} = \frac{{d_2}^{2} }{ {5}^{2} } \\ {d_2}^{2} = \frac{ {5}^{2} }{4 } \\ {d_2}^{2} = \frac{25}{4} \\ {d_2}^{2} = 6.25 \\ \sqrt{{d_2}^{2} } = \sqrt{6.25} \\ \boxed{ \sf{d_2} = 2.5 \: cm}$

Answer: the distance between the two objects is 2.5 cm, if the attraction between them is 8 units.

Learn more about universal law of gravitation here brainly.com/question/27244479

Thanks for joining brainly community!

7 0

1 year ago

I need these all written out on how they're done along with the answer please

taurus [48]

Well, these are quite simple really, especially 1,2,3 and 4. If you read the questions carefully, you can understand it well. You don’t need to know the answer, you just need to understand

8 0

3 years ago