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mixer [17]
3 years ago
12

A 2-kg bowling ball is 1 meter off the ground on a post when it falls. Just before it reaches the ground, it is traveling 4.4 m/

s. Assuming that there is no air resistance, which statement is true?
The mechanical energy is not conserved.

The mechanical energy is conserved.

The intial potential energy is greater than the final kinetic energy.

The initial potential energy is less than the final kinetic energy.
Physics
2 answers:
elena55 [62]3 years ago
5 0

Answer:The correct answer is 'The mechanical energy is conserved'.

Explanation:

Mechanical energy of the body is defined a sum of potential energy and kinetic energy possessed by the body in motion. It is the energy associated with position and motion of the body.

Mechanical energy = Potential energy + Kinetic Energy

The principle of Conservation of Mechanical Energy states that the mechanical energy of the body remains constant as long as the forces acting on the body are conservative forces.

From, this we can say that mechanical energy of the bowling ball with mass of 2 kg falling at speed of 4.4 m/s will remain conserved.

Ira Lisetskai [31]3 years ago
3 0

The mechanical energy is conserved.

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look at the explanation

Explanation:

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Physical anthropology studies _____. the weather the human body the physics of death the material evidence collected at a crime
Elenna [48]

Physical anthropology studies the human body. This discipline is aimed at analyzing the evolution and diversity of human beings.

<h3>What is physical anthropology?</h3>

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5 0
3 years ago
When the sun heats up the suface of the water, the water
nadya68 [22]

Answer:

In the water cycle, evaporation occurs when sunlight warms the surface of the water. The heat from the sun makes the water molecules move faster and faster, until they move so fast they escape as a gas. Once evaporated, a molecule of water vapor spends about ten days in the air.

Explanation:

5 0
3 years ago
A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma
tresset_1 [31]

Answer:

Explanation:

a. Given that:

m- mass of first & second piece, 3m-mass of 3rd piece,\bar v_1-velocity of first piece(-23\dot i \ m/s) and \bar v_2 as velocity of 2nd piece (-23\dot j \ m/s)

Let \bar v_3 be velocity of 3rd piece=?

#Vessel is at rest before explosion. Considering conservation of linear momentum:

m\bar v_1 +m\bar v_2 +3m \bar v_3=0   #Dividing both sides by m, m\neq 0

\bar v_1+ \bar v_2 +3\bar v_3=0\\3\bar v_3=-(\bar v_1 +\bar v_2)\\\bar v_3=-\frac{1}{3}(\bar v_1 +\bar v_2)

#Plug the\bar v_1 ,\bar v_2  values:

\bar v_3=-\frac{1}{3}(-23\dot i -23\dot j)=\frac{1}{3}(23\dot i +23\dot j)

#So the magnitude of the third piece is:

|\bar v_3|=\sqrt{(23/3)^2+(23/3)^2}\\=10.84m/s

Magnitude of the 3rd piece is 10.84 m/s

b. To find direction of the magnitude (as an angle relative to the x-axis), we find \angle \theta. The angle is obtained by getting the tan inverse as:

\theta=tan^-^1(\frac{23/3}{23/3})\\=45\textdegree

-The direction of the magnitude (angle relative to the x-axis) is 45°

6 0
3 years ago
A heat engine does 9200 J of work per cycle while absorbing 22.0 kcal of heat from a hightemperature reservoir. What is the effi
Morgarella [4.7K]

Answer: 9.9%

Explanation: efficiency = (work output /work input) × 100

Note that, 1 kilocalorie = 4184 joules, hence 22kcal = 22× 4184 = 92048 joules.

Work output = 9200 j and work input = 92048 j

Efficiency = (9200/92048) × 100 = 0.099 × 100 = 9.9%

4 0
3 years ago
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