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AlekseyPX
4 years ago
7

What can we say about the rock as it falls to Earth?

Physics
2 answers:
igor_vitrenko [27]4 years ago
8 0

B) It falls at a constant rate of speed.


svet-max [94.6K]4 years ago
4 0

I just took the quiz on USATestprep and got A.) It accelerates as it falls.

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A force of 58 newtons is applied to a crate at an angle of 32° with the horizontal. What is the value of force acting in the y–d
uysha [10]
That should be 58N * sin(32°) = 30.74N 
4 0
3 years ago
Explain What drug Is
12345 [234]

Answer:

A drug is a substance, which alters The functioning of mind and body of a person. Drug can cure disease when taken in right quantities under the supervision of a physician.

3 0
3 years ago
What is the torque τb about axis b due to the force f⃗ ? (b is the point at cartesian coordinates (0,b), located a distance b fr
yKpoI14uk [10]
Check the attached file for the solution.

8 0
3 years ago
According to Newton's Universal Law of Gravitation, when the distance between two interacting objects doubles, the gravitational
maksim [4K]

Answer:

<em>If the distance doubles, the gravitational force is divided by 4</em>

Explanation:

<u>Newton’s Universal Law of Gravitation </u>

Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.

\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}

Where:

m1 = mass of object 1

m2 = mass of object 2

r     = distance between the objects' center of masses

G   = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2

If the distance between the interacting objects doubles to 2r, the new force F' is:

\displaystyle F'=G{\frac {m_{1}m_{2}}{(2r)^{2}}}

Operating:

\displaystyle F'=\frac{1}{4}G{\frac {m_{1}m_{2}}{r^{2}}}

Substituting the original value of F:

\displaystyle F'=\frac{1}{4}F

If the distance doubles, the gravitational force is divided by 4

5 0
3 years ago
You have a 2m long wire which you will make into a thin coil with N loops to generate a magnetic field of 3mT when the current i
Anni [7]

Answer:

<em>radius of the loop =  7.9 mm</em>

<em>number of turns N ≅ 399 turns</em>

Explanation:

length of wire L= 2 m

field strength B = 3 mT = 0.003 T

current I = 12 A

recall that field strength B = μnI

where n is the turn per unit length

vacuum permeability μ  = 4\pi *10^{-7}  T-m/A = 1.256 x 10^-6 T-m/A

imputing values, we have

0.003 = 1.256 x 10^−6 x n x 12

0.003 = 1.507 x 10^-5 x n

n = 199.07 turns per unit length

for a length of 2 m,

number of loop N = 2 x 199.07 = 398.14 ≅ <em>399 turns</em>

since  there are approximately 399 turns formed by the 2 m length of wire, it means that each loop is formed by 2/399 = 0.005 m of the wire.

this length is also equal to the circumference of each loop

the circumference of each loop = 2\pi r

0.005 = 2 x 3.142 x r

r = 0.005/6.284 = 7.9*10^{-4} m = 0.0079 m =<em> 7.9 mm</em>

8 0
3 years ago
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