1 pound = 16 ounces.
70 x 16 = 1120 total ounces per bar.
1120 x $5.05 = $5,656 each.
Answer:
p = 7.2
q = 6.4
Step-by-step explanation:
if the triangles are similar then the side lengths must be proportional :
AC/BA = CD/BE
9/5 = p/4 cross multiply expressions
5p = 36 divide both sides by 5
p = 7.2
same goes for q
9/5 = (q+8)/8 cross multiply expressions
72 = 5(q+8) divide both sides by 5
14.4 = q+8 subtract 8 from both sides
6.4 = q
<span>With 1026 being the mean score on the SAT and StDev of 209, Jessica has a score of 799/209 z-scores above the mean. Her z-score would be 3.823. The mean of the ACT and StDev are 20.8 and 4.8, respectively. A 28 ACT score would be 7.2/4.8 z-scores above the mean, for a z = 1.500. This means that Jessica has the higher z-score.</span>
The height of this triangle would be 10.4
In order to find this, you first must find the length of the sides. Using a manipulated formula for area of an equilateral triangle, we can determine the lengths of the side. Below if the formula.
S = ![\frac{2}{3}3^{\frac{3}{4}} \sqrt{A}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D3%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%20%5Csqrt%7BA%7D%20%20)
In this, S is the length of the side and A is the area. So we plug in and get:
S =
S = ![\frac{2}{3}3^{\frac{3}{4}} 7.89](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D3%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%207.89%20%20)
S = 12
Now that we have the side as 12, we can use the Pythagorean Theorem to find the height. If you split a equilateral triangle down the middle, you are left with two right triangles. Using this right triangle, the hypotenuse would be 12, the first leg would be 6 (half of the base) and the height would be the other leg. So we plug in and solve.
![a^{2} + b^{2} = c^{2}](https://tex.z-dn.net/?f=%20a%5E%7B2%7D%20%2B%20b%5E%7B2%7D%20%3D%20c%5E%7B2%7D%20%20)
![6^{2} + h^{2} = 12^{2}](https://tex.z-dn.net/?f=%206%5E%7B2%7D%20%2B%20h%5E%7B2%7D%20%3D%2012%5E%7B2%7D%20%20)
![36 + h^{2} = 144](https://tex.z-dn.net/?f=%2036%20%2B%20h%5E%7B2%7D%20%3D%20144%20%20)
![h^{2} = 108](https://tex.z-dn.net/?f=%20h%5E%7B2%7D%20%3D%20108%20%20)
h = 10.4
Y greater than or equal to -7