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3 years ago

Please help no du mb answers

Mathematics

1 answer:

vladimir1956 [14]3 years ago

6 0

Answer:

A = (-2,5)

B = (5,5)

the distance between the points is 7

Step-by-step explanation:

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Your school district cancels schools when more than 2.5 inches of snow accumulate on the ground each hour. Snow is currently acc

kari74 [83]

Answer:

Extra snow needed > 0. 3 inch

Step-by-step explanation:

Given that:

Cancelation occurs when > 2.5 inch of snow accumulates each hour

Accumulation rate = 11/5 inch per hour

Extra snow Accumulation needed to cancel. School ;

Extra snow needed > cancelation volume - current rate

Extra snow needed > (2.5 - 11/5)

Extra snow needed > 0. 3 inch

5 0

3 years ago

The area of the trapezoid

ELEN [110]

Answer:

Step-by-step explanation:

The formula of an area of a trapezoid:

$A=\dfrac{b_1+b_2}{2}\cdot h$

b₁, b₂ - bases

h - height

We have b₁ = 10in, b₂ = 5in and h = 11in. Substitute:

$A=\dfrac{10+5}{2}\cdot11=\dfrac{15}{2}\cdot11=7.5\cdot11=82.5\ in^2$

7 0

3 years ago

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Find the coordinates of the intersection of the diagonals of parallelogram GHJK with vertices G(0,2), H(4,2), J(3,0), and K(-1,0

zimovet [89]

Answer:

(1.5,1)

Step-by-step explanation:

The midpoint of G and H is at (2,2).

The midpoint if J and K is (1,0)

The midpoint of the two midpoints is (1.5,1)

You could also i.e. directly ask for the midpoint of H an K, OR, G and J, and you would get the same final result.

8 0

3 years ago

Water whose temperature is at 100∘C is left to cool in a room where the temperature is 60∘C. After 3 minutes, the water temperat

Tju [1.3M]

Answer:

21.68 minutes ≈ 21.7 minutes

Step-by-step explanation:

Given:

$T=60+40e^{kt}$

Initial temperature

T = 100°C

Final temperature = 60°C

Temperature after (t = 3 minutes) = 90°C

Now,

using the given equation

$T=60+40e^{kt}$

at T = 90°C and t = 3 minutes

$90=60+40e^{k(3)}$

$30=40e^{3k}$

$e^{3k}=\frac{3}{4}$

taking the natural log both sides, we get

3k = $\ln(\frac{3}{4})$

3k = -0.2876

k = -0.09589

Therefore,

substituting k in 1 for time at temperature, T = 65°C

$65=60+40e^{( -0.09589)t}$

$5=40e^{( -0.09589)t}$

$e^{( -0.09589)t}=\frac{5}{40}$

$e^{( -0.09589)t}=0.125$

taking the natural log both the sides, we get

( -0.09589)t = ln(0.125)

( -0.09589)t = -2.0794

t = 21.68 minutes ≈ 21.7 minutes

6 0

3 years ago

Can i plz have some help with this

inysia [295]

Answer:

320 in

Step-by-step explanation:

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3 years ago

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