First, we will find the value of k
We can do this by sybstituting y=24, x=6 in;
y=kx and then solve for k
24= k(6)
divide both-side of the equation by 6
24/6 = k
4 = k
k=4
Then when x = 5, we will substitute x=5 and k=4 in; y=kx and then solve for y
y= (4)(5)
y = 20
1. The usable domain of the function is the time period from when the object was dropped (t=0) to when it hits the ground (h(t) = 0, at t=3). The appropriate choice for domain is ...
2) 0 ≤ t ≤ 3
The appropriate choice for range is the range of heights the object may have:
3) 0 ≤ h(t) ≤ 144
2. The domain is a count of people, ...
1) positive integers
The domain is an amount of money, ...
2) positive real numbers
Answer:
a. x = 5, m∠FGH = 22°
b. m∠HGI = 22°
c. m∠FGI = 44°
Step-by-step explanation:
Since GH bisects FGI this means it divides the angle in two equal parts.
a. solving for x means equating them:
5x-3 = 6x-8 =>
5x - 6x = 3 - 8 =>
x = 5.
Both m∠FGH and m∠HGI are 5*5-3 = 22°
c. Add both angles: m∠FGH + m∠HGI = 44°
Answer:
Not sure
Step-by-step explanation:
Its super easy all u have to do is go on tiger math and the first link will take you to it and u put in the question and it will give you a step by step how to do it and it will give you the answer
