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mel-nik [20]
3 years ago
15

There are eight members of a jazz club who are listed below. A concert director can choose some or all of them to be part of a l

arge show. She must choose at least one of them.
Anh, Bryan, Carol, Dan, Elise, Felix, Harry, Joy

In how many different ways can the director choose the members for the show? (The order the members are chosen doesn't matter.)
Mathematics
1 answer:
bagirrra123 [75]3 years ago
8 0

Answer:

40320 ways

Step-by-step explanation:

Given

Members = 8

Required

Number of ways they can be selected

Since, the order does not matter;

They can be selected in 8! ways

8! = 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1

8! = 40320\ ways

<em>Hence, there are 40320 ways which the director can select them for the concert</em>

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Drag the system of equation to the point that represents the solution to the system.
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<span>The point that represents the solution to the system = (-4,5)
========================================================
</span>
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<span>The point that represents the solution to the system = (2,2)
=======================================================
</span>
<span>solving of the system equation: 4x-3y=5  ⇒(1)  and  3x+2y=-9  ⇒(2)
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</span>
<span>The point that represents the solution to the system = (-1,-3)
</span>=======================================================
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<span>The point that represents the solution to the system = (3,4)
=======================================================
</span>solving of the system equation: y=3x-7  ⇒(1)  and  y=2x-5  ⇒(2)
equating (1) and (2)
solve for x and y
we find  x=2  ⇒⇒⇒ y = -1
<span>The point that represents the solution to the system = (2,-1)
=======================================================
</span>
The system equation : y = 6    and  x =-5
<span>The point that represents the solution to the system = (-5,6)
=======================================================
The attached figure represent a conclusion for the answer
</span>







8 0
4 years ago
Read 2 more answers
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