If f(x)=1/9x-2
then f^-1(x) will be
lets assume f(x)=y
y=1/9x-2
y+2=1/9x
9(y+2)=x
f^-1(x)=9(y+2)
rest u can do with the same method
Answer: a) No Solution
b) Infinite Solutions (All Real Numbers)
<u>Step-by-step explanation:</u>
4(g + 8) = 7 + 4g
4g + 32 = 7 + 4g <em>distributed 4 into g + 8</em>
32 = 7 <em> subtracted 4g from both sides</em>
Since the statement is false because 32 ≠ 7, then there is NO SOLUTION
-4(-5h - 4) = 2(10h + 8)
20h + 16 = 20h + 16 <em>distributed</em>
16 = 16 <em>subtracted 20h from both sides</em>
Since the statement is true because 16 = 16, then there are INFINITE SOLUTIONS so x can be all real numbers.
Answer:
(3x - 2)(x - 5)
Step-by-step explanation:
3x² - 17a + 10
(3x - 2)(x - 5)
3x · x = 3x²
3x · -5 = -15x
-2 · x = -2x
-2 · -5 = 10
Answer:
12
Step-by-step explanation:
A = ½(b1 + b2)h
A = (3 + 5)(3)/2
A = 12
You would need a new y-intercept in order for this to be parallel. So you use the points given and the slope and fill it in. 3=-5(-6)+b. 3=30+b. Then subtract 30 from both sides. -27=b. Then just put it all back into slope intercept form. y=-5x-27.
