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kykrilka [37]
3 years ago
7

Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of th

e moon’s surface, making what some consider the longest golf drive in history. Assume one of the golf balls was struck with initial velocity v0 = 28 m/s at an angle θ = 17° above the horizontal. The gravitational acceleration on the moon’s surface is approximately 1/6 that on the earth’s surface. Use a Cartesian coordinate system with the origin at the ball's initial position.
(a) What horizontal distance, R in meters, did this golf ball travel before returning to the lunar surface?
(b) What is the numeric value of the ratio, f, of the horizontal distance traveled on the moon to the horizontal distance the ball would travel on Earth’s surface under the same conditions?
Physics
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer:

(a) Rm = 268.4 m

(b) f = 6

Explanation:

The horizontal range of a projectile is given by the following formula:

R = V₀² Sin 2θ/g

(a)

For moon:

R = Range on moon = Rm

V₀ = Launch Speed = 28 m/s

θ = Launch Angle = 17°

g = acceleration due to gravity on moon = (9.8 m/s²)/6 = 1.63 m/s²

Therefore,

Rm = (28 m/s)²Sin (2*17°)/(1.63 m/s²)

<u>Rm = 268.4 m</u>

(b)

For Earth:

R = Range on Earth = Re

V₀ = Launch Speed = 28 m/s

θ = Launch Angle = 17°

g = acceleration due to gravity on Earth = 9.8 m/s²

Therefore,

Re = (28 m/s)²Sin (2*17°)/(9.8 m/s²)

Re = 44.7 m

Therefore.

f = Rm/Re = 268.4 m/44.7 m

<u>f = 6</u>

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3 years ago
What provides most of the force to allow the runners to move?
kobusy [5.1K]

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3 years ago
An alternating source drives a series RLC circuit with an emf amplitude of 6.04 V, at a phase angle of +30.3°. When the potentia
Vinvika [58]

Answer:

-8.56V

Explanation:

Our values are given by,

e = 6.04 V

Φ = 30.3

VC = 5.32

We can calculate the voltage across the circuit with the emf formula, that is,

e(t) = e* sin(wt)

e(t) = 6.04 * sin(Φ + π)

e(t) = 6.04 * sin(32.5 + 180)

e(t) = -3.245 V

Now, Using Kirchoff Voltage Law,

e(t) - VR- VL - VC = 0

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5 0
3 years ago
car is moving at 40 m/s. At 10 meters the driver spots a deer on the road and instantly steps on the brakes. If the car is 400 k
Mice21 [21]

Answer:

32000 N

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 40 m/s

Distance (s) = 10 m

Final velocity (v) = 0 m/s

Mass (m) of car = 400 Kg

Force (F) =?

Next, we shall determine the acceleration of the the car. This can be obtained as follow:

Initial velocity (u) = 40 m/s

Distance (s) = 10 m

Final velocity (v) = 0 m/s

Acceleration (a) =?

v² = u² + 2as

0² = 40² + (2 × a × 10)

0 = 1600 + 20a

Collect like terms

0 – 1600 = 20a

–1600 = 20a

Divide both side by –1600

a = –1600 / 20

a = –80 m/s²

The negative sign indicate that the car is decelerating i.e coming to rest.

Finally, we shall determine the force needed to stop the car. This can be obtained as follow:

Mass (m) of car = 400 Kg

Acceleration (a) = –80 m/s²

Force (F) =?

F = ma

F = 400 × –80

F = – 32000 N

NOTE: The negative sign indicate that the force is in opposite direction to the motion of the car.

7 0
3 years ago
Cancer and diabetes are two common hereditary diseases.
Klio2033 [76]

It is a true statement that cancer and diabetes are two common hereditary diseases.

<h3>What are hereditary diseases?</h3>

The term hereditary diseases are those diseases that occur in parents and could also be found in their offspring. For many of these hereditary diseases, the mechanism of inheritance is unclear.

However, it is a true statement that cancer and diabetes are two common hereditary diseases.

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Learn more about hereditary diseases:brainly.com/question/9367480?r

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