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3 years ago

What is Newton's law of universal gravitation?

Physics

2 answers:

pshichka [43]3 years ago

8 0

Newton's law of universal gravitation states that a particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. hope this helps =)

r-ruslan [8.4K]3 years ago

3 0

Newton's law of universal gravitation, introduced by Sir Issac Newton, states that an object entices every other object in the universe with a force or pressure that is straightly proportional to the product of their masses and reversely proportional to the square of the distance between them.

In simple expression it is a law declaring that any two masses stimulate each other with a force equal to a persistent of gravitation multiplied by the outcome of the two masses and divided by the square of the distance across the space separating between the two objects or regions.

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Water is formed when two hydrogen atoms bond to an oxygen atom. The hydrogen and the oxygen in this example are different

Goryan [66]

They both are two different elements.SO the answer is Element

8 0

3 years ago

Michael Jordan, el célebre basquetbolista, ganó el torneo de clavadas de la NBA en 1988. Para lograr la hazaña saltó 1.35 metros

kozerog [31]

(a) 0.40 s

First of all, let's find the initial speed at which Jordan jumps from the ground.

The maximum height is h = 1.35 m. We can use the following equation:

$v^2-u^2=2gh$

where

v = 0 is the velocity at the maximum height

u is the initial velocity

$g=-9.8 m/s^2$ is the acceleration of gravity

Solving for u,

$u=\sqrt{-2gh}=\sqrt{-2(-9.8)(1.35)}=5.14 m/s$

The time needed to reach the maximum height can now be found by using the equation

$v=u+gt$

Solving for t,

$t=\frac{v-u}{g}=\frac{0-5.14}{-9.8}=0.52s$

Now we can find the velocity at which Jordan reaches a point 20 cm below the maximum height, so at a height of

h' = 1.35 - 0.20 = 1.15 m

Using again the equation

$v'^2-u^2=2gh'$

we find

$v'=\sqrt{u^2+2gh}=\sqrt{5.14^2+2(-9.8)(1.15)}=1.97 m/s$

And the corresponding time is

$t'=\frac{v'-u}{g}=\frac{1.97-5.14}{-9.8}=0.32s$

So the time to go from h' to h is

$\Delta t = t-t'=0.52-0.32=0.20 s$

And since we have also to take into account the fall down (after Jordan reached the maximum height), which is symmetrical, we have to multiply this time by 2 to get the total time of permanence in the highest 20 cm of motion:

$\Delta t=2\cdot 0.20 = 0.40 s$

(b) 0.08 s

This part is easier since we need to calculate only the velocity at a height of h' = 0.20 m:

$v'^2-u^2=2gh'$

$v'=\sqrt{u^2+2gh}=\sqrt{5.14^2+2(-9.8)(0.20)}=4.74 m/s$

And the corresponding time is

$t'=\frac{v'-u}{g}=\frac{4.74-5.14}{-9.8}=0.04s$

So this is the time needed to go from h=0 to h=20 cm; again, we have to take into account the motion downwards, so we have to multiply this by 2:

$\Delta t = 2\cdot 0.04 =0.08 s$

8 0

4 years ago

What would you predict for this elephant's stride frequency? That is, how many steps per minute will the elephant take?

Sonja [21]

` You can consider T to be in units of seconds/step. Frequency is the inverse of period, so
1/T = frequency and has units of steps per second. There will be 60 times as many steps in a minute.

8 0

3 years ago

Read 2 more answers

A 210 kg meteoroid is heading toward the earth accelerates by 2.4 × 105 m/s2.

lidiya [134]

According to Newton's second law of motion, Force is the product of mass and acceleration of the object.
So, F = m * a

Here, m = 210 Kg
a = 2.4 * 10⁵ m/s²

Substitute their values,
F = 210 * 2.4 * 10⁵ N
F = 504 * 10⁵ N
F = 5.04 * 10⁷ N

In short, Your Answer would be Option B

Hope this helps!

6 0

3 years ago

If the truck has a mass of 2,000 kilograms , what's its momentum?(v=35 m/s)

katen-ka-za [31]

Answer:

$\boxed {\boxed {\sf 70,000 \ kg*m/s}}$