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WARRIOR [948]
3 years ago
12

A group of 2 adults and 4 children spent $38 on tickets to a museum. A group of 3 adults and 3 children spent $40.50 on tickets

to the museum. Based on this information, how much is an adult ticket, and how much is a child ticket?
Mathematics
2 answers:
mrs_skeptik [129]3 years ago
4 0

Answer:

adult $8.00

child $5.50

Step-by-step explanation:

Let the price of 1 adult ticket = x.

Let the price of 1 child ticket = y.

2x + 4y = 38

3x + 3y = 40.5

Multiply the first equation by 3. Multiply the second equation by -2. Then add them.

         6x + 12y = 114

(+)      -6x - 6y = -81

-----------------------------

                  6y = 33

y = 33/6

y = 5.5

2x + 4y = 38

2x + 4(5.5) = 38

2x + 22 = 38

2x = 16

x = 8

Answer:

adult $8.00

child $5.50

MA_775_DIABLO [31]3 years ago
3 0

Answer:

An adult ticket is $8.00 and a child's ticket is $5.50.

Step-by-step explanation:

We form a system of 2 equations and solve them.

Let a be the price of adult ticket and c the price of a child's.

2a + 4c = 38         (A)

3a + 3c = 40.5      (B)

Multiply equation A by 3 and equation B by -2:

6a + 12c = 114

-6a - 6c = -81        Adding these 2 equations:

0 + 6c = 33

c = 33/6 = 5.5.

Now we substitute for c in equation A:

2a + 4(5.5) = 38

2a = 38 - 22

2a = 16

a = 6.

Let's now check these results by substitution in equation B:

3a + 3c = 40.5

3(8) + 3(5.5) = 24.0 + 16.5 = 40.5

- so it checks out.

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Mekhanik [1.2K]

The probability that the events (a) they both picked Limca = 0.04, (b) Ademola only picked Pepsi = 0.32, (c) They both picked the same brand = 0.33 (d) They picked different brand=0.67.

<h3>What is probability?</h3>

Probability is the fraction of the required outcome event divided by the number of possible outcomes of events.

Total possible outcome of the event of picking drinks contained in the crate = 19

Hence, we can compute the following as follows;

(a) The probability they both picked Limca = (4/19)×(3/18)

Limca = 12/342

Limca = 0.04

(b) The probability Ademola only picked pepsi = 6/19

pepsi = 0.32

(c) The probability they both picked the same brand = (9/19)×(8/18)+(6/19)×(5/18)+(4/19)×(3/18)

=(72+29+12)/342

= 114/342

= 0.33

(d) The probability they picked different brand = (9/19)×(6/18)+(9/19)×(4/18)+(6/19)×(9/18)+(6/19)×(4/18)+(4/19)×(9/18)+(4/19)×(6/18)

The probability they picked different brand = (54+36+54+24+36+24)/342

The probability they picked different brand = 228/332

The probability they picked different brand = 0.67

Therefore, the probability for events (a) is 0.04, (b) is 0.32, (c) is 0.33 and (d) is 0.67.

Know more about probability here: brainly.com/question/24830485

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