A group of 2 adults and 4 children spent $38 on tickets to a museum. A group of 3 adults and 3 children spent $40.50 on tickets
to the museum. Based on this information, how much is an adult ticket, and how much is a child ticket?
2 answers:
Answer:
adult $8.00
child $5.50
Step-by-step explanation:
Let the price of 1 adult ticket = x.
Let the price of 1 child ticket = y.
2x + 4y = 38
3x + 3y = 40.5
Multiply the first equation by 3. Multiply the second equation by -2. Then add them.
6x + 12y = 114
(+) -6x - 6y = -81
-----------------------------
6y = 33
y = 33/6
y = 5.5
2x + 4y = 38
2x + 4(5.5) = 38
2x + 22 = 38
2x = 16
x = 8
Answer:
adult $8.00
child $5.50
Answer:
An adult ticket is $8.00 and a child's ticket is $5.50.
Step-by-step explanation:
We form a system of 2 equations and solve them.
Let a be the price of adult ticket and c the price of a child's.
2a + 4c = 38 (A)
3a + 3c = 40.5 (B)
Multiply equation A by 3 and equation B by -2:
6a + 12c = 114
-6a - 6c = -81 Adding these 2 equations:
0 + 6c = 33
c = 33/6 = 5.5.
Now we substitute for c in equation A:
2a + 4(5.5) = 38
2a = 38 - 22
2a = 16
a = 6.
Let's now check these results by substitution in equation B:
3a + 3c = 40.5
3(8) + 3(5.5) = 24.0 + 16.5 = 40.5
- so it checks out.
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Hello :
f(x) = (x − h)2 + k: a <span> vertex of( 2, 3)
h=2 and k=3</span>
Total marks in JEE = 400
Your marks = 70
Let your percent be x.
Then,
(x/100) × 400 = 70
=> x/100 = (70/400)
=> x/100 = 0.175
=> x = 0.175 × 100
=> x = 17.5
So, you got 17.5% marks.