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HACTEHA [7]
3 years ago
14

3p + 7q = 55 7p + 7q = 91 What is p and q

Mathematics
2 answers:
kkurt [141]3 years ago
7 0

Step-by-step explanation:

3p + 7q = 55

7p + 7q = 91

(-)

-4p=-36

p=9

q=4

valentinak56 [21]3 years ago
7 0

Answer:

p = 9 and q = 4

Step-by-step explanation:

3p + 7q = 55 -- (1)

7p + 7q = 91 -- (2)

(2) - (1) : 4p = 36

               p = 9 -- (3)

Substituting (3) into (1),

27 + 7q = 55

7q = 28

q = 4 -- (4)

Therefore, p = 9 and q = 4

If this helps you, please mark brainliest!

Have a nice day!

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Answer:

100 times

Step-by-step explanation:

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In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha
siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95,  P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

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