Answer:One can do a two-proportion test and find that the z-value for different is 1.28 (or -1.28, depending how one sets up the test).
The p-value for that is 0.20, so by most tests this is not statistically significant.
Said another way, if there had been no change in the interval, the probability of having a repeat sample at least this different would be 0.20.
The parameter one is attempting to determine is the true proportion of adults in the US who say they like pizza.
For those who think it is 50%, it is essentially 100% likely that it is not 50% but much higher, around 75-77%.
Answer:
wait a second I help you
Step-by-step explanation:
Answer:
Step-by-step explanation:
You have this expression:
You already know that the value of the variable "x" is:
And the value of the variable "y" is:
Therefore, you can substitute the value of the variable "x" and the value of the variable "y" into the expression.
Then you get:
You have to do 91/13 which is 7 which means that each hen lays 7 eggs per week so the unit rate is 7
15=0.5x+7
0.5x=12
X=24
His weekly allowance is $24