Answer:
23 i think
Step-by-step explanation:
The correct format of the question is
At the end of 2006, the population of Riverside was 400 people. The population for this small town can be modeled by the equation below, where t represents the number of years since the end of 2006 and P represents the number of people.
Based on this model, approximately what was the increase in the population of Riverside at the end of 2009 compared to the end of 2006?
(A) 291
(B) 691
(C) 1040
(D) 1440
Answer:
The increase in the population at the end of 2009 is 291 people
Step-by-step explanation:
We are given the equation as
where
P = No of People
t= No of Years
it is given that in the year 2006 the population is 400
this will only happen when we take t= 0
so for
Year value of t
2006- t = 0
2007- t = 1
2008- t = 2
2009 t = 3
No of people in 2009 will be

= 400*1.728
P = 691.2
Since the equation represents no of people so it can't be in decimals, Therefore the population will be 691
Increase = P(2009) - P(2006)
= 691 - 400
= 291
The increase in the population at the end of 2009 is 291 people.
Answer:
Step-by-step explanation:
X^2-10x-8=0
Solve simultaneously
Answer:
1) Slope-intercept form
2) 9200
3) 2 months
4) (0,200)
Step-by-step explanation:
A shelter had 200 animals in foster homes at the beginning of spring and the number of animals in foster homes at the end of the summer could be represented by
y=3000x+200 ............ (1)
Where x is the number of months and y is the number of animals.
1) The equation (1) is written in the slope-intercept form of a straight line equation.
2) After 3 months means x = 3 and the number of animals in the foster home after 3 months will be (3000 ×3 + 200) = 9200 (Answer)
3) Let after x months the animal population will become 6200.
So, 6200 = 3000x + 200
⇒ 3000x = 6000
⇒ x = 2 months (Answer)
4) If we put x = 0 in equation (1), then we get y = 200.
So, (0,200) is a point on the graph of the line. (Answer)
The numbers in pie are 3.14159