Complete question:
I failed in finding the complete question. However, in the answer and explanation boxes, I will determine the genotypes of labrador for each color.
Answer:
- For black-haired dogs: BBEE, BBEe, BbEE, BbEe
- For brown (chocolate) color: bbEE, bbEe
- For Yellow color: BBee, Bbee, bbee.
Explanation:
Due to technical problems, you will find the complete answer and explanation in the attached files.
Answer:A
Explanation:<em>The core is a solid in the middle and molten on top of it</em>
B. Cloning because the selections don’t make sense
Assuming Hardy-Weinberg equilbrium, we have
p + q = 1
where p = frequency of dominant allele and q = frequency of recessive allele. So
p = 1 - q = 1 - 0.04 = 0.96
Consequently we have
• p² = 0.9216 = frequency of hom ozygous domininant genotype
• pq = 0.0768 = frequency of heterozygous genotype
• q² = 0.0016 = frequency of hom ozygous recessive genotype
since
p² + 2pq + q² = 1
Answer:
A. There is no common deletion.
Explanation:
The correct answer to the given question is the option A. There is no common deletion.
In the study of the muscle disorder, the samples taken and the effects observed concludes that there was no common deletion among the analysed families and their mitochondrial DNA.
