Steps of protein sythesis

Technician a says that the intake valve runs hotter than the exhaust valve because the intake valve has the greater surface area

Misha Larkins [42]

Answer:

Technician B......

6 0

4 years ago

The apical ends of intestinal cells face the intestinal channel and have long processes that facilitate the absorption of nutrie

Serggg [28]

Answer:

microvilli, actin filaments

Explanation:

The apical ends of intestinal cells face the intestinal channel and have long processes that facilitate the absorption of nutrients. the name of these processes is microvilli and actin filaments from the cytoskeletal element forms their internal skeleton.

3 0

4 years ago

The apterous gene in Drosophila encodes a protein required for wing patterning and growth. It is also known to function in nerve

poizon [28]

Answer:

is also known to function in nerve development, fertility, and viability. When human and mouse genes whose protein products closely resemble apterous were used to generate ... [USA] 96: 2165–2170), the apterous mutant phenotype was rescued. ... patterns in the transgenic Drosophila were similar to normal apterous.

Explanation:

It is also known to function in nerve development, fertility, and viability. When human and mouse genes whose protein products closely resemble apterous were used to ... patterns in the transgenic Drosophila were similar to normal apterous. ... for normal wing patterning and growth whereas mutation in the gene (apterous ...is also known to function in nerve development, fertility, and viability. When human and mouse genes whose protein products closely resemble apterous were used to generate ... [USA] 96: 2165–2170), the apterous mutant phenotype was rescued. ... patterns in the transgenic Drosophila were similar to normal apterous.

5 0

3 years ago

In hamsters, we can examine the genes for coat color and eye color which are linked:B = brown coat, b = white coat, G = green ey

Inessa [10]

Answer:

10.2 cM

Explanation:

Given,

pure breeding parent 1 : BBgg = brown coat and pink eyes

pure breeding parent 2 : bbGG = white coat and green eyes

BBGG X bbgg = F1 = BbGg ( All are brown with green eyes )

When F1 progeny is test crossed with white coat and pink eyes hamster:

BbGg X BbGg = F2 =

brown, pink eyes = 99 = parental

white, green eyes = 103 = parental

brown, green eyes = 12 = recombinant

white, pink eyes = 11 = recombinant

Recombination frequency =

(total number of recombinants / total progeny ) * 100

= [( 11 + 12 ) / ( 99 + 103 + 12 + 11 )] * 100 = (23/225)*100 = 0.102 * 100 = 10.2 %

1 % recombination frequency = 1 cM distance between genes

Hence, the distance between B and G gene is 10.2 cM

4 0

4 years ago

Which of these is most likely a result of a high

aliya0001 [1]

Answer: I am confused maybe add some choices next time please and thank you

Explanation:

4 0

3 years ago

Steps of protein sythesis ​

Steps of protein sythesis