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3 years ago

Can you please explain how to solve this?

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

7 0

Answer:

Step-by-step explanation:

hello,

as this is a parallelogram we can write that BE = DE so

15x + 4 = 9x + 6

<=> 15x - 9x + 4 = 6

<=> 6x = 6 - 4 = 2

<=> x = 2/6 = 1/3

so BE = DE = 15/3+4=5+4=9

so BD = BE + DE = 9 + 9 = 18

the correct answer is 18

hope this helps

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If x^2y-3x=y^3-3, then at the point (-1,2), (dy/dx)?

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If you're using the app, try seeing this answer through your browser: brainly.com/question/2866883

_______________

   dy
Find —— for an implicit function:
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x²y – 3x = y³ – 3

First, differentiate implicitly both sides with respect to x. Keep in mind that y is not just a variable, but it is also a function of x, so you have to use the chain rule there:

$\mathsf{\dfrac{d}{dx}(x^2 y-3x)=\dfrac{d}{dx}(y^3-3)}\\\\\\
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Applying the product rule for the first term at the left-hand side:

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Now, isolate —— in the equation above:
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$\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3=3y^2\cdot \dfrac{dy}{dx}}\\\\\\
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x = – 1 and y = 2

$\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{-\,2\cdot (-1)\cdot 2+3}{(-1)^2-3\cdot 2^2}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{4+3}{1-12}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{7}{-11}}\\\\\\\\ \therefore~~\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=-\,\dfrac{7}{11}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>implicit function derivative implicit differentiation chain product rule differential integral calculus</em>

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