Answer:
2k
Step-by-step explanation:
Let k is the ratio between two variables or y = kx
when x double, means: y = k (2x) = 2kx quantity y will change with a ratio 2k
Answer:
Javier's parents set aside $1500 when he was born
Step-by-step explanation:
This is a simple interest problem.
The simple interest formula is given by:
In which E is the interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.
In this question, we have that:
We have to find P. So
Javier's parents set aside $1500 when he was born
Answer:
(a) ¬(p→¬q)
(b) ¬p→q
(c) ¬((p→q)→¬(q→p))
Step-by-step explanation
taking into account the truth table for the conditional connective:
<u>p | q | p→q </u>
T | T | T
T | F | F
F | T | T
F | F | T
(a) and (b) can be seen from truth tables:
for (a) <u>p∧q</u>:
<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>
T | T | F | F | T | T
T | F | T | T | F | F
F | T | F | T | F | F
F | F | T | T | F | F
As they have the same truth table, they are equivalent.
In a similar manner, for (b) p∨q:
<u>p | q | ¬p | ¬p→q | p∨q</u>
T | T | F | T | T
T | F | F | T | T
F | T | T | T | T
F | F | T | F | F
again, the truth tables are the same.
For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))
Answer:
C. Three
Step-by-step explanation:
We want to solve the equation for n:
14,580 = 20,000(9/10)^n
14580/20000 = 729/1000 = (9/10)^n
(9/10)^3 = (9/10)^n . . . . . . write the left side as a cube
3 = n . . . . . . equate exponents
After year 3, the value will be $14,580.
_____
You can use logarithms to find n:
log(0.729) = n×log(0.9) . . . . . . taking the log of the 2nd line above
log(0.729)/log(0.9) = n = 3
