Select all input values for which f(x)=3<br>

Two number cubes are tossed. What is P(4, 6)?<br><br> O.1/6<br> O.1/12<br> O.1/3<br> O.1/36

Bezzdna [24]

The value of P(4, 6) when the two number cubes are tossed is 1/36

<h3>How to determine the probability?</h3>

On each number cube, we have:

Sample space = {1, 2, 3, 4, 5, 6}

The individual probabilities are then represented as:

P(4) =1/6

P(6) =1/6

The value of P(4, 6) when the two number cubes are tossed is:

P(4, 6) = P(4) * P(6)

This gives

P(4, 6) = 1/6 * 1/6

Evaluate

P(4, 6) = 1/36

Hence, the value of P(4, 6) when the two number cubes are tossed is 1/36

Read more about probability at:

brainly.com/question/24756209

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6 0

1 year ago

Solving each proportions 10/8=n/10

RideAnS [48]

Answer:

n=12.5

Step-by-step explanation:

10/8=n/10

multiply the denominator and numerators 10 ad 10=100 divide by 8=12.5

3 0

3 years ago

If line segment BH = 3, line segment BF = 10, line segment GH= 2, find HD 15 11 10.5 ?

pav-90 [236]

HD = 10.5

Step-by-step explanation:

Given BH = 3, GH = 2, BF = 10

Step 1: To find HF:

HF = BF – BH

HF = 10 – 3

HF = 7

Step 2: To find HD:

We know that if two chords intersects inside a circle, the product of the lengths of the segments of one chord equals the product of the lengths of the segments of the other chord.

⇒ GH × HD = BH × HF

⇒ 2 × HD = 3 × 7

⇒ HD = 10.5

Hence, the value of HD = 10.5.

5 0

3 years ago

Read 2 more answers

6th grade distributive property page 2 only 2 questions

Stolb23 [73]

What are the questions?

7 0

3 years ago

Read 2 more answers

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0

3 years ago

Select all input values for which f(x)=3​

Select all input values for which f(x)=3