Select all input values for which f(x)=3
1 answer:
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Answer:
see explanation
Step-by-step explanation:
Using the cofunction identities
tan(90 - A) = cotA and cscA = sec(90- A)
Consider the left side
tanA + tan(90 - A)
= tanA + cotA
= +
=
=
= ×
= secA × cscA
= secA. sec(90 - A) = right side ⇒ verified
Hello!
To graph the solution x>-2 on a number, the first thing you need to do is to mark -2 on the number line using an open circle.
The reason you would use an open circle (like o instead of •) is because the symbols > and < represent a solution that is greater than or less than the number, but does not include it. In the case of x>-2, the solutions are all greater than than -2 but because the symbol does not state x can be -2 (if it were you would be using <span>≥</span> which states x can be any number greater than or equal to -2) all values of x are any numbers that are greater than -2 such as -1, 0, or 5.
Then, once you have plotted the open circle on -2, because all your solutions are greater than -2, draw a line on the number line (make it bold if you have to) going towards the right to show this.
To graph the solution x>-2 on a number, the first thing you need to do is to mark -2 on the number line using an open circle.
The reason you would use an open circle (like o instead of •) is because the symbols > and < represent a solution that is greater than or less than the number, but does not include it. In the case of x>-2, the solutions are all greater than than -2 but because the symbol does not state x can be -2 (if it were you would be using <span>≥</span> which states x can be any number greater than or equal to -2) all values of x are any numbers that are greater than -2 such as -1, 0, or 5.
Then, once you have plotted the open circle on -2, because all your solutions are greater than -2, draw a line on the number line (make it bold if you have to) going towards the right to show this.