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4 years ago

Select all input values for which f(x)=3

Mathematics

1 answer:

Alexxandr [17]4 years ago

3 0

Answer:

Step-by-step explanation:

x=-3

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Check if the following equality is true for all values of variables: (a–3c)(4c+2a)+3c(a+3c)=(2a–c)(3c+5a)–8a^2

BabaBlast [244]

Answer:

True for all values of a, b and c.

Step-by-step explanation:

(a–3c)(4c+2a)+3c(a+3c)=(2a–c)(3c+5a)–8a^2

Left side:

(a–3c)(4c+2a)+3c(a+3c)

= 4ac + 2a^2 - 12c^2 - 6ac + 3ac + 9c^2

= 2a^2 + ac - 3c^2

Right side:

(2a–c)(3c+5a)–8a^2

= 6ac + 10a^2 - 3c^2 - 5ac - 8a^2

= 2a^2 + ac - 3c^2.

So we see that the left side is identical to the right side so it is true for all values of the variables.

3 0

3 years ago

4(х – 1) = 3х – 1 what is x

netineya [11]

Answer:

x=3 hope I helped you! :)

4 0

3 years ago

Find the slope of the line through (2, -3) and (-4, 3).

Mars2501 [29]

Answer:

Slope= -1x OR -x

Step-by-step explanation:

rise over run: y2 - y1 / x2 - x1

= 3 - (-3) / -4 - 2

= 6 / -6

= -1

3 0

4 years ago

Read 2 more answers

Give an example of a defined term and explain what is defined.

masha68 [24]

A defined terms can be combined and form with the undefined terms to complete the definition of the term. A vertex for example, it is form when two lines are meet to each other or there would be an intersection of two lines. I hope you are satisfied with my answer and feel free to ask for more

5 0

3 years ago

Differentiate Vx(x + 2) with respect to x.

Travka [436]

Answer:

$y'= \frac{3x+2}{2\sqrt{x} }$

General Formulas and Concepts:

Calculus

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

$y=\sqrt{x} (x+2)$

Step 2: Rewrite

$y=x^{\frac{1}{2} } (x+2)$

Step 3: Differentiate

Product Rule [Basic Power/Chain Rule]: $y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)$
Simplify: $y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}$
Rewrite: $y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}$
Add: $y'= \frac{3x+2}{2\sqrt{x} }$

7 0

3 years ago

Select all input values for which f(x)=3​

Select all input values for which f(x)=3