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sergey [27]
3 years ago
15

PLEASE HELP I NEED HELP WITH THIS ASAP. PLEASE show work, thank you. Will give branliest

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0
If the slope is 5 perpendicular would be -1/5 just flip the slope around
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brilliants [131]
Same thing as what you did on the bottom. Find numbers with both 7 as the base and numbers that add to 14 on the top. Possibilities:
1) 7^10•7^4
2)7^6•7^8
37^2•7^12
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Graph y = 4x + 2 where is it grqphed at
cestrela7 [59]
Starting point: (0, 2) and can go to (1, 6).
This shows the slope and y-intercept. Hope this helps.
5 0
3 years ago
PLEASE HELP <br><br> Which relation is a function?!
tia_tia [17]

The answer is the third one aka C.

There must not be two points on the same y-axis because that doesn't make a function but a relation instead.

C. doesn't have 2 points on same y-axis and therefore the third picture is the relation that's a function.

4 0
3 years ago
100 POINTS, WILL MARK BRAINLIEST! If h(x) = f[f(x)] use the table of values for f and f ′ to find the value of h ′(1).
victus00 [196]

Answer:

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Step-by-step explanation:

Given that  h(x)=f(f(x))

now to find h(x)=f(f(x)) from the given functions f(x) and f'x

let h(x)=f(f(x))

Then put x=1 in above function we get

h(1)=f(f(1))

=f(3) (from the table f(1)=3 and f(3)=6)

Therefore h(1)=6

Now to find h'(1)

Let

h^{\prime}(x)=f^{\prime}(f^\prime(x)) (since  h(x)=f(f(x)) )

put x=1 in above function we get

h^{\prime}(1)=f^{\prime}(f^\prime(1))

=f^{\prime}(2)    (From the table f^\prime(1)=2 and f^\prime(2)=5)

h^{\prime}(1)=5

Therefore h^{\prime}(1)=5

4 0
3 years ago
Read 2 more answers
Write an inequality for the graph
natima [27]
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A closed circle means the inequality will be greater than (>) or less than (<)

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A narrowing pointing left to increasingly negative values means the inequality is getting lesser (< or ≤)

So for this graph with an open circle and rightward pointing arrow, “x” will be some number on the number line greater than the first point of -38:
x > -38
6 0
3 years ago
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