
where
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is the CDF for
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.
By symmetry of the distribution, you then have
1.A 2.B 3.B 4.D !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11
It is equivalent too 5.3 and 5.30
Answer:
10.82 revolutions per mintue
Step-by-step explanation:
First we need the circumference of the cirkel. As you may know the formula for that is 2×pi×r, with r as the radius of the cirkel. So 2×pi×15=30pi centimeters or 94.24 centimeters. Now we will calculate the fraction of 17 centimeters on 94.24 centimeters. 17/94.24=0.18. That is how fast the wheel will spin. To get it in minutes we now do: 0.18×60=10.82 revolutions per minute.