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user100 [1]
2 years ago
10

A baby blue whale weighed 5520 pounds at birth. After two days, the baby weighed 5710 pounds. After 14 days, the baby weighed 81

80 pounds. Does this situation indicate a proportional relationship? If so, what is the constant of proportionality?
Mathematics
2 answers:
iVinArrow [24]2 years ago
7 0
No it’s not a proportional relationship
ANTONII [103]2 years ago
3 0

I popped in the values to desmos, and it doesnt make a line. i dont think it is a proportional relationship... either that or im dumb lol sorry

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A truck travels 2,365 miles at an average speed of 55 miles per hour.At that speed, how long will it take the truck to complete
disa [49]

Answer:

Step-by-step explanation:

Givens

d = 2365 miles

r = 55 miles / hour

t = ?

Formula

d = r * t

Solution

d = r * t

2365 = 55 * t               Divide by 55

2365/55 = t

t = 43 hours.

5 0
2 years ago
When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was o
borishaifa [10]

Answer:

\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The expected values for all the categories is :

E_i =\frac{150}{3}=50

And then the statistic would be given by:

\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4

And the best option would be:

b. 4

Step-by-step explanation:

For this problem we have the following observed values:

Yes 40 No 60 No Opinion 50

And we want to test the following hypothesis:

Null hypothesis: All the opinions are uniformly distributed

Alternative hypothesis: Not All the opinions are uniformly distributed

And for this case the statistic would be given by:

\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The expected values for all the categories is :

E_i =\frac{150}{3}=50

And then the statistic would be given by:

\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4

And the best option would be:

b. 4

7 0
3 years ago
What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1,5)?
romanna [79]
m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{5 - (-1)}{-1 - 3} = \frac{5 + 1}{-4} = \frac{6}{-4} = \frac{3}{-2} = -1\frac{1}{2}
  y - y₁ = m(x - x₁)
y - (-1) = -1¹/₂(x - 3)
  y + 1 = -1¹/₂(x) + 1¹/₂(3)
  y + 1 = -1¹/₂x + 4¹/₂
      - 1              - 1
         y = -1¹/₂x + 3¹/₂

  4x + y - 2 = 0
            + 2 + 2
       4x + y = 2
4x - 4x + y = -4x + 2
               y = -4x + 2
         y - y₁ = m(x - x₁)
      y - (-3) = -4(x - 4)
         y + 3 = -4(x) + 4(4)
         y + 3 = -4x + 16
             - 3            - 3
               y = -4x + 13

  2x - 3y - 5 = 0
             + 5 + 5
2x - 2x - 3y = -2x + 5
             -3y = -2x + 5
              -3         -3
                y = ²/₃x - 1²/₃
       y - (-3) = -1¹/₂(x - 4)
          y + 3 = -1¹/₂(x) + 1¹/₂(4)
          y + 3 = -1¹/₂x + 6
              - 3              - 3
                y = -1¹/₂x + 3

8 0
3 years ago
Read 2 more answers
A famrmer grows 128 red tomato plants
Scorpion4ik [409]

If 32 people buy an equal amount of his tomatoes, then each person willl get 4 tomatoes.

6 0
3 years ago
(PLEASE HELP)simplify 2 with an exponent of 5 over 3 with an exponent of 2 and the equation has an exponent of 4
Nostrana [21]
Assuming you mean this as your problem I hope I can assist you.
( \frac{2^5}{3^2})^4
So just apply the exponent rule to start, which is (a/b)^c = a^c/b^c
This translates to....
\frac{(2^5)^4}{(3^2)^4}
Now apply the exponent rule (a^b)^c = a^bc
Which translates to 3^2 * 4 which is refined to 3^8
So now we have....
\frac{(2^5)^4}{3^8}
Just apply the exponent rule (a^b)^c
So we get 2^5 * 4 which refines to 2^20
Therefore our final answer is 2^20/3^8


4 0
2 years ago
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