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Sidana [21]
3 years ago
14

Will Give Brainliest!

Computers and Technology
2 answers:
liraira [26]3 years ago
7 0

You have to wait a little bit until you can give the person brainiest. You mostly give it to someone who gave a great answer. :)

Sliva [168]3 years ago
7 0

Answer:

If two person had given your answer then there is a option of mark as brainliest. Click there in the option of mark as brainliest in which you like the answer most. If any one person has given answer then after some days you will a notification to mark his/her answer as brainliest. By this you can mark an answer as brainliest.

Explanation:

hope this helped

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You decide to buy some stocks for a certain price and then sell them at anotherprice. Write a program that determines whether or
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no_of_shares = int(input("Enter the number of shares: "))

purchase_price = float(input("Enter the purchase price of the stock: "))

sale_price = float(input("Enter the sale price of the stock: "))

total_stock_price = purchase_price*no_of_shares

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total_sale_price = sale_price*no_of_shares

commission_while_selling = total_sale_price*0.03

net_gain_or_loss = total_sale_price - (total_spend_on_buying + commission_while_selling)

if(net_gain_or_loss<0):

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else:

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Matching parentheses. An math expression may have a number of parentheses like (, ), [, ], { and }. Each openning parenthesis (,
Solnce55 [7]
C++ Code

#include
using namespace std;

bool match(const char exp[],const int s)
{
// declare a character array to perform stack operations
char stack[s];

// declare top and initialize to -1 and flag to 0
int top=-1,i,flag=0;

// visit all characters in the expression string
for(i=0;i {
// if the character is [ or ( or { then push it into stack
if(exp[i]=='[' || exp[i]=='(' || exp[i]=='{')
{
top++;
stack[top]=exp[i];
}
// if the character is ] or ) or } then check conditions
else if(exp[i]==']' || exp[i]==')' || exp[i]=='}')
{
// check stack is empty or not
if(top!=-1)
{
// check all possible failure conditions
if(exp[i]==')' && (stack[top] == '{' || stack[top]=='['))
{
flag = 1;
break;
}
else if(exp[i]==']' && (stack[top] == '{' || stack[top]=='('))
{
flag = 1;
break;
}
else if(exp[i]=='}' && (stack[top] == '(' || stack[top]=='['))
{
flag = 1;
break;
}
top--;
}
else
{
flag=1;
break;
}
}
}
// after visiting all characters of expression string check if stack is not empty and flag is 1. if any one of the condition is true return false. otherwise return true

if(top>=0 || flag==1)
return false;
else
return true;
}

int main()
{

// declare character array to store expression
char exp[10000];
cout<<"Enter an Expression"<
// read expression from user
cin.getline(exp, 10000);
int s=0;

// find the length of the expression string
for(int i=0;exp[i]!='\0';i++)
{
s++;
}

// call the match function
bool status = match(exp,s);

// print the result based on value returned by match() function
if(status == 1)
cout<<"true"< else
cout<<"false"<
}


Sample Input/Output is attached

3 0
2 years ago
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