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damaskus [11]
3 years ago
5

Find the equation of the circle with center at (3,-2) and radius of 3.

Mathematics
1 answer:
AURORKA [14]3 years ago
3 0

Answer:

The equation of the circle is (x - 3)² + (y + 2)² = 9

Step-by-step explanation:

The form of the equation of a circle is (x - h)² + (y - k)² = r², where

  • h is the x-coordinate center of the circle
  • k is the y-coordinate of the center of the circle
  • r is the radius of the circle

∵ The center of a circle is (3, -2)

∴ x-coordinate of the center is 3

∴ y-coordinate of the center is -2

∴ h = 3 and k = -2

∵ The radius of the circle is 3

∴ r = 3

→ Substitute them in the form of the equation above

∵ (x - 3)² + (y - -2)² = (3)²

∴ (x - 3)² + (y + 2)² = 9

∴ The equation of the circle is (x - 3)² + (y + 2)² = 9

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Answer:

-4409/100

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You are given the information that P(A) = 0.30 and P(B) = 0.40.
Ad libitum [116K]

Answer:

1.B. No. You need to know the value of P(A and B). 2.C. Yes P(A and B) =0, so P(A or B) = P(A) + P(B).

Step-by-step explanation:

We can solve this question considering the following:

For two mutually exclusive events:

\\ A_{1}\;and\;A_{2}

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) (1)

An extension of the former expression is:

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1} and A_{2}) (2)

In <em>mutually exclusive events,</em> P(A and B) = 0, that is, the events are <em>independent </em>one of the other, and we know the probability that <em>both events happen</em> <em>at the same time is zero</em> (P(A <em>and</em> B) = 0). There are some other cases in which if event A happens, event B too, so they are not mutually exclusive because P(A <em>and</em> B) is some number different from zero. Notice the difference between <em>OR</em> and <em>AND. The latter implies that both events happen at the same time.</em>

In other words, notice that the formula (2) provides an extension of formula (1) for those events that are not <em>mutually exclusive</em>, that is, there are some cases in which the events share the same probabilities in a way that these probabilities <em>must be subtracted</em> from the total, so those probabilities in common do not "inflate" the actual probability.

For instance, imagine a person going to a gas station and ask for checking both a tire and lube oil of his/her car. The probability for checking a tire is P(A)=0.16, for checking lube oil is P(B)=0.30, and for both P(A and B) = 0.07.

The number 0.07 represents the probability that <em>both events occur at the same time</em>, so the probability that this person ask for checking a tire or the lube oil of his/her car is:

P(A or B) = 0.16 + 0.30 - 0.07 = 0.39.

That is why we cannot simply add some given probabilities <em>without acknowledging if the events are or not mutually exclusive</em>, whereas we can certainly add the probabilities in question when we know that both probabilities are <em>mutually exclusive</em> since P(A and B) = 0.

In conclusion, knowing the events are mutually exclusive <em>does</em> provide <em>extra information</em> and we can proceed to simply add the probabilities of either event; thus, the answers are those in which <em>we need to previously know the value of P(A and B)</em>.  

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