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Ludmilka [50]
3 years ago
14

which type of classroom enable students to attend lectures without being physically present with the teacher

Computers and Technology
2 answers:
nadezda [96]3 years ago
6 0

A browser-based, virtual classroom with a facility of web conferencing platform developed for teaching online.

It can create the online school, manage courses of studies and users and make face to face interaction between the teacher and the student.

An approach is different than some of the other platforms out there as the motive is to deliver a platform that presents your classes, workshops and tutoring sessions in a modern, professional way.

Live virtual classrooms enable students to attend lectures without being physically present in the classroom

--

Ivanshal [37]3 years ago
4 0

Answer:The answer is VIRTUAL, NOT ONLINE!! Plato accepted virtual and my daughter got it correct.

Explanation:

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Broadcasting sites, greater internet freedom,. 
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You are the Emergency Management Director of a small island nation. Your nation has come under Cyber-attack and the attackers ha
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okay actually what are you trying to get an answer for

Explanation:

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An executable file that was determined to be infected with a virus was terminated from the running processes list. However, afte
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Mostly Trojan will has multiple version and I love u virus extra.

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3 years ago
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
One foot equals 12 inches. Write a function named feet_to_inches that accepts a number of feet as an argument and returns the nu
fenix001 [56]

Answer:

def feet_to_inches( feet ):

      inches = feet * 12

      print(inches, "inches")

feet_to_inches(10)

Explanation:

The code is written in python.  The unit for conversion base on your question is that 1 ft = 12 inches. Therefore,

def feet_to_inches( feet ):

This code we define a function and pass the argument as feet which is the length in ft that is required when we call the function.

inches = feet * 12

Here the length in ft is been converted to inches by multiplying by 12.

print(inches, "inches")

Here we print the value in inches .

feet_to_inches(10)

Here we call the function and pass the argument in feet to be converted  

       

8 0
3 years ago
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