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kupik [55]
3 years ago
15

If a code word is defined to be a sequence of different letters chosen from the 10 letters A, B, C, D, E, F, G, H, I, and J, wha

t is the ratio of the number of 5-letter code words to the number of 4-letter code words?
Computers and Technology
1 answer:
netineya [11]3 years ago
5 0

Answer:

The answer is 6:1 .

Explanation:

We don't need to have prior knowledge of combination or permutation.

Count the way to chose 4 letters.As given in the question chose sequence of different letters

For first place we have 10 letter

For second place we have 9 letter as one is already out

For 3 place we have 8 letter as two letter are already out

For 4 place we have 7 letter as three letter are already out

Total group of 4 letters = 10 * 9 *8*7

Similarly form group of 5 letters we have

Total group of 5 letters = 10 * 9* 8 * 7*6

then Calculating ratio between 4 and 5

We have,

Group 5 : Group 4 ::10 * 9* 8 * 7*6:10 * 9 *8*7

                              : : 30240 : 5040

divide by 5040 on both side we get

Group  5: Group 4 :: 6 : 1

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Explanation: I play Mobile legends a lot so I know this

4 0
3 years ago
What type of internet connection do you think you'd get in Antarctica?
rusak2 [61]
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3 0
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AleksandrR [38]

Answer: what do  you need help with?

Explanation:

4 0
2 years ago
Read 2 more answers
Consider the following code:
Art [367]

Answer:

The output is 252

Explanation:

To get the output, I'll analyze the lines of code one after the other.

Here, user enters 78. So, start = 78

start = int(input("Enter the starting number: "))

Here, user enters 45. So, stop = 45

stop = int(input("Enter the ending number: "))

This initializes x to -10

x = -10

This initializes sum to 0

sum = 0

This iterates from 78 to 46 (i.e. 45 + 1) with a decrement of -10 in each successive term

for i in range (start, stop, x):

This adds the terms of the range

     sum = sum + i

This prints the calculated sum

print(sum)

The range starts from 78 and ends at 46 (i.e. 45 + 1) with a decrement of -10.

So, the terms are: 78, 68, 58 and 48

And Sum is calculated as:

Sum = 78 + 68 + 58 +48

Sum = 252

<em>Hence, 252 will be printed</em>

8 0
3 years ago
Please help.
storchak [24]

Hey mate!

Answer:

import java.util.*;

class Max Min

{

public static void main()

{

int a,b,c,x,y,z,m,n;

Scanner in=new Scanner(System.in);

System.out.println("Enter three unequal numbers:");

a=in.nextInt();

b-in.nextInt();

c=in.nextInt();

x=Math.max(a,b);

y=Math.max(b,c);

z=Math.max(c,a);

m=Math.min(x,y);

n=Math.min(z,m);

System.out.printLn("Second Smallest Number is:"+n);

}

}

Explanation:

  1. here scanner class is used
  2. here java.util package is used

<em><u>h</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>he</u></em><em><u>lped</u></em><em><u> you</u></em><em><u>:</u></em><em><u>)</u></em>

4 0
3 years ago
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