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3 years ago

Please answer me- How do you make friends.? Im a loner. YALL GOTTA HELP ME:(

Engineering

2 answers:

denpristay [2]3 years ago

6 0

Realize your fear is in your head. The first step is to develop a healthy mental image of meeting new people.

Start small with people you know.

Get yourself out there.

Take the first step.

Be open.

Get to know the person.

Connect with genuinity.

Be yourself.

lorasvet [3.4K]3 years ago

3 0

Get open mind start small the that steps and steps forwards in life you will get friend on the way I promise you :)

You might be interested in

What is the first step in the Design Process *

Gennadij [26K]

Answer:

Define the problem

I hope this helps!

Explanation:

The problem must be know before you can develop and solution, generate concepts, or construct and test a prototype

8 0

3 years ago

Using the AASHTO procedure, determine the thickness required for a base and a surface layer over existing subgrade. The structur

garri49 [273]

Answer:

<u>the thickness required would be 12 inch HMA and granular base layer of 6 inches</u>

Explanation:

structural number = 4.5

stone base course material coefficient = 0.13

hma material layer coefficient = 0.40

drainage coefficient = 0.90

we will use layered analysis procedure to get thickness

D1 >= sN1/a1

when we cross multiply,

sN1 = a1D1 >=sN1

D2 >= -sN2-sN1/a2m2

sN2* + sN1* >= sN2

D3 >= sN3-(sN1*+sN2*)/a2m2

where a1,a2,a3 = layer coefficient

d1 d2 d3 = actual thickness

m2,m3 = coefficient of base

a1 = 0.4

a1 = 0.13

sN = 4.5

m2 = 0.9

D1 >= sN1/a1 = 4.5/0.4

= 11.25

thickness of surface = 12 inches

a1D1 = 0.4x12 = 4.8

we have value of sN2 = 5.5

(5.5 -4.8)/(0.13*0.9)

= 0.7/0.117

= 5.9829 inches

approximately 6 inches

so the pavement will have 12inch HMA surface and 6 inches granular base layer.

7 0

3 years ago

A) Gravity attracts horizontally downwards the weight of any object such a building or a part of building. (True / False)

PtichkaEL [24]

Answer:

True
True
False
True

Explanation:

True
True
False
True

3 0

3 years ago

Two very long concentric cylinders of diameters D1 = 0.42 m and D2 = 0.5 m are maintained at uniform temperatures of T1 = 950 K

MrRa [10]

Answer:

Q=33.34 KW/m

Explanation:

Given that

D₁=0.42 m

A₁= π D₁ L

For unit length

A₁= π D₁ = 0.42 π m²

D₂=0.5 m

A₂= 0.5 π m²

ε₁= 1 ,ε₂= 0.55

T₁=950 K ,T₂ = 500 K

$Q=\dfrac{\sigma (T_1^4-T_2^4)}{\dfrac{1-\varepsilon _1}{A_1\epsilon _1}+\dfrac{1-\varepsilon _2}{A_2\epsilon _2}+\dfrac{1}{A_1F_{12}}}$

F₁₁+F₁₂= 1

F₁₁= 0

So, F₁₂= 1

$Q=A_1\dfrac{\sigma (T_1^4-T_2^4)}{\dfrac{1-\varepsilon _1}{\epsilon _1}+A_1\dfrac{1-\varepsilon _2}{A_2\epsilon _2}+1}$

$Q=0.42\pi \dfrac{5.67\times 10^{-8}(950^4-500^4)}{\dfrac{1-1}{1}+0.42\pi\times \dfrac{1-0.55}{0.5\pi\times 0.55}+1}$

Q=33.34 KW/m

3 0

4 years ago

What should be the internal diameter of a glass tube if capillary rise is not exceed 2.0 mm?

prohojiy [21]

Answer:

diameter is 14.83 mm

Explanation:

given data

height = 2 mm

to find out

internal diameter

solution

we consider here material is glass and liquid is water and angle is zero if no capillary rise

we apply here capillary rise formula that is

Capillary rise h = 2T / [ r×ρ×g ] ....................1

put here r is radius and ρ = 1000 kg/m³, T = 72.7 × $10^{-3}$ N/m all value in equation 1

Capillary rise h = 2T / [ r×ρ×g ]

r = 2T / [ h×ρ×g ]

d/2 = 2T / [ h×ρ×g ]

d/2 = 2( 72.7 × $10^{-3}$ ) / [ 2× $10^{-3}$ ×1000×9.8 ]

d = 0.0148336 m

so diameter is 14.83 mm

6 0

3 years ago