Answer:
Define the problem
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Explanation:
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Answer:
<u>the thickness required would be 12 inch HMA and granular base layer of 6 inches</u>
Explanation:
structural number = 4.5
stone base course material coefficient = 0.13
hma material layer coefficient = 0.40
drainage coefficient = 0.90
we will use layered analysis procedure to get thickness
D1 >= sN1/a1
when we cross multiply,
sN1 = a1D1 >=sN1
D2 >= -sN2-sN1/a2m2
sN2* + sN1* >= sN2
D3 >= sN3-(sN1*+sN2*)/a2m2
where a1,a2,a3 = layer coefficient
d1 d2 d3 = actual thickness
m2,m3 = coefficient of base
a1 = 0.4
a1 = 0.13
sN = 4.5
m2 = 0.9
D1 >= sN1/a1 = 4.5/0.4
= 11.25
thickness of surface = 12 inches
a1D1 = 0.4x12 = 4.8
we have value of sN2 = 5.5
(5.5 -4.8)/(0.13*0.9)
= 0.7/0.117
= 5.9829 inches
approximately 6 inches
so the pavement will have 12inch HMA surface and 6 inches granular base layer.
Answer:
diameter is 14.83 mm
Explanation:
given data
height = 2 mm
to find out
internal diameter
solution
we consider here material is glass and liquid is water and angle is zero if no capillary rise
we apply here capillary rise formula that is
Capillary rise h = 2T / [ r×ρ×g ] ....................1
put here r is radius and ρ = 1000 kg/m³, T = 72.7 ×
N/m all value in equation 1
Capillary rise h = 2T / [ r×ρ×g ]
r = 2T / [ h×ρ×g ]
d/2 = 2T / [ h×ρ×g ]
d/2 = 2( 72.7 ×
) / [ 2×
×1000×9.8 ]
d = 0.0148336 m
so diameter is 14.83 mm