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Montano1993 [528]
3 years ago
11

A two-dimensional flow field described by

Engineering
1 answer:
Oduvanchick [21]3 years ago
5 0

Answer:

the answer is

Explanation:

<h2>  We now focus on purely two-dimensional flows, in which the velocity takes the form </h2><h2>u(x, y, t) = u(x, y, t)i + v(x, y, t)j. (2.1) </h2><h2>With the velocity given by (2.1), the vorticity takes the form </h2><h2>ω = ∇ × u = </h2><h2> </h2><h2>∂v </h2><h2>∂x − </h2><h2>∂u </h2><h2>∂y </h2><h2>k. (2.2) </h2><h2>We assume throughout that the flow is irrotational, i.e. that ∇ × u ≡ 0 and hence </h2><h2>∂v </h2><h2>∂x − </h2><h2>∂u </h2><h2>∂y = 0. (2.3) </h2><h2>We have already shown in Section 1 that this condition implies the existence of a velocity </h2><h2>potential φ such that u ≡ ∇φ, that is </h2><h2>u = </h2><h2>∂φ </h2><h2>∂x, v = </h2><h2>∂φ </h2><h2>∂y . (2.4) </h2><h2>We also recall the definition of φ as </h2><h2>φ(x, y, t) = φ0(t) + Z x </h2><h2>0 </h2><h2>u · dx = φ0(t) + Z x </h2><h2>0 </h2><h2>(u dx + v dy), (2.5) </h2><h2>where the scalar function φ0(t) is arbitrary, and the value of φ(x, y, t) is independent </h2><h2>of the integration path chosen to join the origin 0 to the point x = (x, y). This fact is </h2><h2>even easier to establish when we restrict our attention to two dimensions. If we consider </h2><h2>two alternative paths, whose union forms a simple closed contour C in the (x, y)-plane, </h2><h2>Green’s Theorem implies that   </h2><h2> </h2><h2> </h2><h2> </h2><h2> </h2><h2> </h2><h2></h2><h2></h2>
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marshall27 [118]

Answer:

All will be Explained below.

Explanation:

1) Under which Condition can a soil be chemically Stabilize.

Answer

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7 0
3 years ago
What is the resistance of a resistor if the current flowing through it is 3mA and the voltage across it is 5.3V?
Flura [38]

Answer: 1766.667 Ω = 1.767kΩ

Explanation:

V=iR

where V is voltage in Volts (V), i is current in Amps (A), and R is resistance in Ohms(Ω).

3mA = 0.003 A

Rearranging the equation, we get

R=V/i

Now we are solving for resistance. Plug in 0.003 A and 5.3 V.

R = 5.3 / 0.003

= 1766.6667 Ω

= 1.7666667 kΩ

The 6s are repeating so round off to whichever value you need for exactness.

6 0
1 year ago
Draw the schematics for the following two battery connections. Can you explain the value of the output voltage in the series con
matrenka [14]

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5 0
2 years ago
What are the factors of production in business? Land, labor, and capital land, capital, and interest land, labor, and customer b
kozerog [31]

Answer:

  • <em><u> Land, labor, and capital </u></em>

Explanation:

The <em>factors of production </em>are the resources that are used to produce goods and services.

By definition resources are scarce.

<em>Land</em> includes everything that comes from the land, that can be used as raw material to produce other materials; for instance, water, minerals, wood.

<em>Labor</em>  is the work done by anybody, not just at a factory but at any enterpise that produce a good or a service. For instance, the work done by a person in a bank or a restaurant.

<em>Capital</em> is the facilites (buildings), machinery, equipments, tools that the persons use to produce goods or services. For instance, a computer, a chemical reactor, or a pencil.

Nowadays, also entrepreneurship is included as a <em>factor of production</em>, since it is the innovative skill of the entrepeneurs to combine land, labor and capital what permit the production of good and services.

6 0
3 years ago
Read 2 more answers
A cylindrical brass rod has a length of 5.00cm extending from a holder and a diameter of 4.50mm. Its Young's modulus is 98.0GPa.
Galina-37 [17]

Answer:

elongation of the brass rod is 0.01956 mm

Explanation:

given data

length = 5 cm = 50 mm

diameter = 4.50 mm

Young's modulus = 98.0 GPa

load = 610 N

to find out

what will be the elongation of the brass rod in mm

solution

we know here change in length formula that is express as

δ = \frac{PL}{AE}    ................1

here δ is change in length and P is applied load  and A id cross section area and E is Young's modulus and L is length

so all value in equation 1

δ = \frac{PL}{AE}  

δ = \frac{610*50}{\frac{\pi}{4} * 4.50^2 * 98*10^3}  

δ = 0.01956 mm

so elongation of the brass rod is 0.01956 mm

7 0
3 years ago
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