Let’s first be less vague. We’ll say pressure, there’s an intensive property. Also, let’s identify a material. We’ll say water as its vapor behavior is so well understood.
So, if what you are asking is would the pressure of saturated water vapor that boiled off of pure water be different than the pressure of saturated water vapor that was generated from a solution (let’s not require it be saturated) of, say, water and sugar that was mostly sugar, if the temperatures are equal then the answer is yes. Why? Because the boiling points are different.
For example, if you were to find saturated vapor in a system at atmospheric pressure above water, then that steam would be at 212 °F and 0 psig (14.7 psia). Water vapor above a 50%+ DS (dissolved solid to water by mass percentage) solution of dextrose and water would have a partial pressure lower than atmospheric in the same setting. Why? Because we still have a ways to go before that solution will actually boil.
Now, when you do reach its boiling point you will have a vapor that is at 0 psig but it will not be saturated. It will instead be superheated, as the dextrose molecules have a negligible vapor pressure. The vapor you get is basically all water (with some tiny entrained but not vaporized sugar droplets), and as the boiling point was greater than the saturated temperature for that pressure it’s superheated out of the gate. If you were to take it out of that system and allow it to desuperheat on its own (without the addition of a water spray) it would lose pressure to achieve saturation.
I hope that helped.
Answer:
Distance between manholes = 166.67 (Unit) (Approx)
Explanation:
Given:
Invert elevation = 2605
New Invert elevation = 2610
Grade % = 3% = 0.03
Find:
Distance between manholes
Computation:
Grade % = (Change in elevation)/Distance between objects
0.03 = (2610-2605)/Distance between manholes
0.03 = 5 / Distance between manholes
Distance between manholes = 166.67 (Unit) (Approx)
Answer:
Algorith does not work.
Explanation:
One of the ways to obtain the Dekker Algorithm is through a change in the declaration, that is, a declaration that can be executed at the exact moment it leaves the critical section. This way it is possible that the statement,
turn = 1-i / * P0 sets turn to 1 and P1 sets turn 0 * /
It can be changed to,
turn = (turn +1) \% n / * n = number or processes * /
The result will allow to define if it works or not, that is, if it is greater than 2 the algorithm will not be able to work.
Given this consideration we can say that,
<em>- The dead lock does not occur, because the mutual is imposed (if a resource unit has been assigned to a process, then no other process can access that resource).</em>
<em>- There is the possibility of starving if the shift is established in a non-contentious process.</em>
Directly it can be concluded that there is a possibility of starvation so the algorithm could not work, despite the fact that mutual exclusion guarantees that a dead block does not occur.
Explanation:
The following evidence could be used by an engineer;
The study of areodynamics and the fact that there are four parameters lift, weight, thrust and drag can explain the flying of airplanes in sky
Lift is a force that pushes the plane to rise ad it is actually the design of wings and their movements that create this lifting force
Weight is the force necessary to consider to make the plane fly and land
Then comes thrust, developed via engines or propellers of an airplane.
Last force is drag which defines the force needed to keep the plane pass through air.
A well calculated combination of all four forces actually make a plan fly