Answer:
Explanation:
The impact between bat and ball is an extremely violent one, in which the bat imparts a huge force on the ball thereby causing it to change directions and gain speed. Consider a baseball weighing 5.125oz (mass = 0.145kg) which approaches the bat at a speed of 90mph (40.2m/s). After the collision with the bat, with a contact time of 0.7milliseconds (0.0007s)[1,2] the bat has a speed of 110mph (49.1m/s) in the opposite direction.
Answer:
Velocity of skater after throwing the snowball is 2.57 m/s
Explanation:
Given :
Mass of skater, M = 62.2 kg
Mass of snowball, m = 0.145 kg
Velocity of snowball relative to ground, v = 39.3 m/s
Consider v₁ be the velocity of skater after throwing the snowball.
According to the problem, initially the velocity of skater and snowball is same. So,
Velocity of skater before throwing snowball, u = 2.66 m/s
Applying conservation of momentum,
Momentum before throwing snowball = Momentum after throwing snowball
(M + m) u = Mv₁ + mv
Substitute the suitable values in the above equation.
v₁ = 2.57 m/s
Answer:
The SI unit of current is ampere which measures the flow of electric charge across a surface at the rate of one coulomb per second.
Use KE= 1/2mv^2
So...
50,000=(.5)(1,000)v^2
50,000=500 x v^2
Divide 500 on both sides
100 = v^2
Square root both sides to get rid of v^2
Therefore v = 10 m/s