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MariettaO [177]
3 years ago
5

Science Seminar Question: Why did Vehicle 2 fall off the cliff in Claire's test of the collision scene but Vehicle 2 did not fal

l off the cliff in the film Iceworld Revenge?

Physics
1 answer:
asambeis [7]3 years ago
8 0

Complete Question:

Check the file attached to get the complete question

Answer:

In the film Ice word Revenge, vehicle 2 did not fall of the cliff because, Weight_{vehicle 1} < Weight_{vehicle 2} but in Claire's test, vehicle 2 off the cliff because Weight_{vehicle 1} \geq Weight_{vehicle 2}

Explanation:

In Claire's test, the weight of vehicle 1 is either equal to or greater than the weight of vehicle 2, so it was sufficient to push it down the cliff.  In the film Ice word revenge, the weight of vehicle 1 is less than the weight of vehicle 2, it is not sufficient to make it fall off the cliff ( Note: Looking exactly the same in the movie, as Claire claimed, does not mean they have the same mass). Therefore if Claire wants a collision that will not make the vehicle 2 fall off the cliff, he should collide it with a vehicle of lesser mass/weight.

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At what angle (relative to the horizontal) should a curve 52 m in radius be banked if no friction is required to prevent the car
velikii [3]

Answer:

Banking angle, \theta=15.77^{\circ}

Explanation:

It is given that,

Radius of the curve, r = 52 m

Speed of the car, v = 12 m/s

Acceleration due to gravity, g=9.8\ m/s^2

Let the curved is banked at an angle of \theta with respect to the horizontal. It is given by :

tan\theta=\dfrac{v^2}{rg}

tan\theta=\dfrac{(12)^2}{52\times 9.8}                

\theta=15.77^{\circ}

So, the curve is banked at an angle of 15.77 degrees wrt the horizontal. Hence, this is the required solution.

7 0
4 years ago
What is the last planet discovered?
Bumek [7]
Pluto is the last planet discovered in our solar system.
6 0
4 years ago
What is the best example of the purpose of scientific notation?
Gemiola [76]

The correct answer would be to express large and small numbers.


3 0
3 years ago
A boy of mass 30.0 kg is sledding down a 70.0-m slope starting from rest. The slope is angled at 15.0° below the horizontal. Aft
Studentka2010 [4]

The speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

<h3>Their speed at the bottom</h3>

Apply the principle of conservation of energy,

E(up) - E(friction) = E(bottom)

mg sin(15) + ¹/₂(M + m)u² - μ(M + m)cos 15 = ¹/₂(M + m)v²

v = \sqrt{2[\frac{mgd \ sin15 \ + \frac{1}{2}(M + m)u^2 \ -\mu (M + m)g cos\ 15 }{M + m}] }

where;

  • u is the speed of the after 28 m

u = √2gh

u = √(2gL sin15)

u = √(2 x 9.8 x 28 x sin 15)

u = 11.92 m/s

v = \sqrt{2[\frac{(30)(9.8)(70) \ sin15 \ + \frac{1}{2}(30 + 50)(11.92)^2 \ - 0.12 (30 + 50)9.8 cos\ 15 }{30 + 50}] }\\\\v = 16.52 \ m/s

Thus, the speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

Learn more about speed here: brainly.com/question/6504879

#SPJ1

8 0
2 years ago
The mass of an object with 500 J of kinetic energy moving with a velocity of 5 m/s is
Ann [662]

40kg

Explanation:

Given parameters:

Kinetic energy  = 500J

Velocity = 5m/s

Unknown:

Mass of the object = ?

Solution:

Kinetic energy is the energy due to motion of a body. It is expressed as:

          K.E = \frac{1}{2} mv²

  m is the mass of the body

  v is the velocity

 To find the mass, make it the subject of the expression:

         m = \frac{2 K.E}{v[tex]^{2}}[/tex]

          m =   \frac{2 x 500}{5[tex]^{2}}[/tex] = 40kg

Learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

4 0
4 years ago
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