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Setler [38]
3 years ago
7

How much heat is absorbed by a 125 g sample of water when it is heated from 25.20 ºc to 32.80 ºc? the specific heat of water is

4.184 j/g ºc?
Physics
1 answer:
Fofino [41]3 years ago
4 0
We can use the equation of
E = mc△T
To calculate the total heat absorbed.
E is the total heat absorbed (energy used)
m is mass.
c is specific heat capacity and
△T is the temperature change.
E = 125 x 4.184 x (32.8 - 25.2)
E = 3974.8 J
Therofre the total heat absorbed is 3974.8 joules.
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Answer:

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Explanation:

Let assume that car accelerates uniformly, in that case, we can obtain the value of acceleration by using the following equation of motion:

v = v_{o}+a\cdot t

Where:

v_{o} - Initial velocity, measured in meters per second.

v - Final velocity, measured in meters per second.

a - Acceleration, measured in meters per square second.

t - Time, measured in seconds.

Now, we clear acceleration within expression:

a = \frac{v-v_{o}}{t}

Initial and final velocities are now converted from kilometers per hour into meters per second:

v_{o} = \left(108\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

v_{o} = 30\,\frac{m}{s}

v = \left(135\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

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If we know that t = 3.5\,s, then, the average acceleration of the car is:

a = \frac{37.5\,\frac{m}{s}-30\,\frac{m}{s} }{3.5\,s}

a = 2.143\,\frac{m}{s^{2}}

The average acceleration of the car is 2.143 meters per square second.

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