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Ket [755]
3 years ago
9

-3 is less than or equal to W and W is less than or equal to 4

Mathematics
1 answer:
ANEK [815]3 years ago
8 0

Answer:

-3 ≤ W ≤ 4

I hope this helps!

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Pls help solve<br> find t
IgorC [24]

Answer:

-t = -8 ×5

-t = -40

t= 40

good luck have a nice day

7 0
2 years ago
a soccer ball is kicked into the air, and it’s path can be modeled with a quadratic function. the table shows the time, t, in se
Black_prince [1.1K]

Answer:

f(t)=-2 t(t-5)

-just took the assignment

4 0
3 years ago
Sandra throws an object straight up into the air with an initial velocity of 38 ft/s from a platform that is 30 ft above the gro
Makovka662 [10]

Answer:

The answer is C.

Step-by-step explanation:

Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.

In this case, the initial postion is a platform 30ft above ground so h0=+30

The initial velocity is 38 ft/s straight up into the air so v0=+38

h(t)=-16t2+38t+30

When the object hits the ground, h=0.

h=-16t2+38t+30=0

Simplifying 8t2-19t-15=0

(8t+5)(t-3)=0

t=-5/8 or 3

As time cannot be -ve, t=3s. The answer is C.

6 0
2 years ago
Read 2 more answers
1- find the first term= ?, 90, 540, 3240
Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

4 0
3 years ago
Convert the following <br><br>250cm to m​
dmitriy555 [2]

100 cm = 1m

1 cm = 1/100

250 cm = 1/100*250

= 2.5m

This is Right answer...

4 0
3 years ago
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