Question

Write an equation in standard form passing through the points (-2, 0) and (-3, -1). I know the answer to the question, but I do not know how to solve this question to get to the answer. I will give the title to whoever gives the most understandable explanation to the question and answer. I will be glad to answer to help you give to create an explanation. Thank you and good luck.

Answer 1

Answer:

$y - x = 2$

Step-by-step explanation:

Given

Points (-2,0) and (-3,-1)

Required

Equation of Line

The first step is to determine the slope of the line; using the following formula

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$Where\ (x_1,y_1) = (-2,0)\ and\ (x_2,y_2) = (-3,-1)$

$m = \frac{y_2 - y_1}{x_2 - x_1}$ becomes

$m = \frac{-1 -0}{-3 - (-2)}$

$m = \frac{-1}{-3 +2}$

$m = \frac{-1}{-1}$

$m = 1$

The next is to determine the equation of the line using any of the points

The formula is as thus;

$m = \frac{y - y_1}{x - x_1}\ or\ m = \frac{y - y_2}{x - x_2}$

Using $m = \frac{y - y_1}{x - x_1}$

$Where\ (x_1,y_1) = (-2,0)\ and\ m =1$

$1 = \frac{y-0}{x - (-2)}$

$1 = \frac{y-0}{x +2}$

$1 = \frac{y}{x +2}$

Multiply both sides by x + 2

$(x+2)*1 = \frac{y}{x +2} * (x+2)$

$(x+2)*1 = y$

$x+2 = y$

$y = x + 2$

Subtract x from both sides

$y - x = x - x +2$

$y - x = 2$

Hence, the equation of the line in standard form is $y - x = 2$