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Kryger [21]
3 years ago
14

Complete the square for 5x^2-30x=5

Mathematics
2 answers:
xxMikexx [17]3 years ago
8 0

Answer: (x-3)^2=10

Step-by-step explanation:

Nikitich [7]3 years ago
3 0

Solve for x over the real numbers: by completing the square:

5 x^2 - 30 x = 5

Divide both sides by 5:

x^2 - 6 x = 1

Add 9 to both sides:

x^2 - 6 x + 9 = 10

Write the left hand side as a square:

(x - 3)^2 = 10

Take the square root of both sides:

x - 3 = sqrt(10) or x - 3 = -sqrt(10)

Add 3 to both sides:

x = 3 + sqrt(10) or x - 3 = -sqrt(10)

Add 3 to both sides:

Answer: | x = 3 + sqrt(10) or x = 3 - sqrt(10)

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Answer:

I think it's 140 not sure

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Which expression is equivalent to -8? A=-2^-3 B=(-1/2)^-3 C=(1/2)^-3 D=2^-3
sladkih [1.3K]

Answer:

The answer is option B.

Step-by-step explanation:

( -  \frac{1}{2} ) ^{ - 3}  = ( - 2) ^{3}  =  - 8

Hope this helps you

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Pedro fill the glass 2 4 full with orange juice write a fraction with a denominator of 6 that is greater than 2/4 what is the an
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Consider the following 8 numbers, where one labelled
AlladinOne [14]
<h3>Answers:     x = -17  and   x = 64</h3>

====================================================

Explanation

Consider three scenarios:

  • A) The value of x is the smallest of the set (aka the min)
  • B) The value of x is the largest of the set (aka the max)
  • C) The value of x is neither the min, nor the max. So 8 < x < 39.

These scenarios cover all the possible cases of what x could be. It's either the min, the max, or somewhere in between the min and max.

--------------------

We'll start with scenario A.

If x is the min, then that must mean 39 is the max as it's the largest of the set {18, 36, 16, 39, 27, 8, 34}

The range is 56, so,

range = max - min

56 = 39 - x

56+x= 39

x = 39-56

x = -17  which is one possible answer

--------------------

If instead we go with scenario B, then x is the max and 8 is the min

range = max - min

56 = x - 8

56+8 = x

64 = x

x = 64 is the other possible answer

--------------------

Lastly, let's consider scenario C. If x is not the min or the max, then it's somewhere between the min 8 and max 39. in short, 8 < x < 39.

Note that range = max - min = 39-8 = 31 which is not the range of 56 that we want. So there's no way scenario C can be possible here.

7 0
2 years ago
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