5.What is the chemibal formula for lead (II) iodide

Chemistry

1 answer:

Tpy6a [65]4 years ago

4 0

Answer: The chemical formula for lead (II) iodide is $PbI_2$

Explanation:

Lead (II) iodide is a ionic compound because it are formed by transference of electrons between metals and non metals.The bond formed between a metal and a non-metal is always ionic in nature.

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The nomenclature of ionic compounds is given by:

1. Positive is written first followed by the oxidation state of metal in roman numerals in square brackets.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

The chemical formula for lead (II) iodide is $PbI_2$

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