The propane undergoes a combustion reaction (combustion reactions are reactions in which a substance reacts with oxygen and burns).
To calculate the number of moles of propane, we use the molar mass of propane, which is 44.0 g/mol.
To convert mol C3H8 into mol CO2, we use the molar ratio between the two substances. The molar ratio is seen by the coefficients in front of the each substance in the reaction, so the ratio of C3H8 to CO2 is 1 to 3, with 3 moles of CO2 produced for every mole of C3H8 reacting.
To convert mol CO2 into molecules of CO2, we use Avogadro's number:
There are 6.022 × 10²³ molecules per mole of any substance:
Answer:
ionic
it is a mixture of a nonmetal and a metal which is what makes ionic compounds
covalent is a nonmetal and nonmetal
Explanation:
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Answer:
The molar volume of a gas expresses the volume occupied by 1 mole of that respective gas under <em>certain temperature and pressure conditions</em>.
scientists use molar volume to measure gas because it it tells us about volume occupied by gas.
<u><em>Molar volume</em></u>
- The molar volume of a gas tell us about volume occupied by 1 mole of that respective gas under certain temperature and pressure conditions.
- At STP(Standard Temperature and Pressure) condition which is equal to 22.4 L for 1 mole of any ideal gas at a temperature equal to 273.15 K and a pressure equal to 1.00 atm.
- The molar volume of a gas is derived from the ideal gas law <u><em>PV=NRT</em></u>
Answer:
-3135.47 kJ/mol
Explanation:
Step 1: Write the balanced equation
C₆H₆(l) + 7.5 O₂(g) ⇒ 6 CO₂(g) + 3 H₂O(g)
Step 2: Calculate the standard enthalpy change of the reaction (ΔH°r)
We will use the following expression.
ΔH°r = ∑np × ΔH°f(p) - ∑nr × ΔH°f(r)
where,
n: moles
ΔH°f: standard enthalpies of formation
p: products
r: reactants
ΔH°r = 6 mol × ΔH°f(CO₂(g)) + 3 mol × ΔH°f(H₂O(g)) - 1 mol × ΔH°f(C₆H₆(l)) - 7.5 mol × ΔH°f(O₂(g))
ΔH°r = 6 mol × (-393.51 kJ/mol) + 3 mol × (-241.82 kJ/mol) - 1 mol × (48.95 kJ/mol) - 7.5 mol × 0 kJ/mol
ΔH°r = -3135.47 kJ
Since this enthalpy change is for 1 mole of C₆H₆(l), we can express it as -3135.47 kJ/mol.