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3 years ago

Which of the following pairs of substances can be broken down chemically?

Chemistry

1 answer:

Ket [755]3 years ago

5 0

Methane and water because they are both compounds

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Use the balanced equation given below to solve the problem that follows: Calculate the mass in grams of water produced along wit

saveliy_v [14]

Answer: 1.98 g

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given volume}}{\text{Molar volume}}$

$\text{Moles of} CO_2=\frac{5.0L}{22.4L}=0.22moles$

The balanced given equation is:

$C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)$

According to stoichiometry :

4 moles of $CO_2$ will produce = 2 moles of $H_2O$

Thus 0.22 moles of $CO_2$ will produce= $\frac{2}{4}\times 0.22=0.11moles$ of $H_2O$

Mass of $H_2O=moles\times {\text {Molar mass}}=0.11moles\times 18g/mol=1.98g$

Thus 1.98 g of water is produced along with 5.0 L of $CO_2$ at STP

6 0

3 years ago

Synthesis of propionic acid

Karolina [17]

Answer:

H2C=CH2 + H2O + CO → CH3CH2CO2H. It is also produced by the aerobic oxidation of propionaldehyde.

5 0

3 years ago

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Do atoms lend and borrow electrons from inner shells

zaharov [31]

False. They don't borrow electrons at all. They already have their respective electron affinities. This is called as electronegativity, and it's an occurence where it already has its own from its actual structure. It never borrows any electrons at all.

4 0

3 years ago

temperature change in Metals metal specific heat initial temperature final temperature copper 0.39 100°C 27°C aluminum 0.90 100°

kolbaska11 [484]

Answer:

Explanation:

6 0

4 years ago

50 POINTS PLEASE HELP!

Aleks04 [339]

Answer: The molar mass of the gas is 9.878 g/mol.

Explanation:

According to Graham's law, the rate of diffusion is inversely proportional to square root of molar mass of gas.

$Rate = \frac{1}{\sqrt{M}}$

where,

M = molar mass of gas

As given gas diffuses 1/7 times faster than hydrogen gas. So, its molar mass is calculated as follows.

$\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\$

where,

$M_{1}$ = molar mass of hydrogen gas

$M_{2}$ = molar mass of another given gas

$R_{1}$ = rate of diffusion of hydrogen

$R_{2}$ = rate of diffusion of another given gas = $\frac{1}{7}R_{1}$

Substitute the values into above formula as follows.

$\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\\frac{R_{1}}{\frac{1}{7}R_{1}} = \sqrt{\frac{M_{2}}{2}}\\7 \times 1.414 = M_{2}\\M_{2} = 9.878 g/mol$

Thus, we can conclude that the molar mass of the gas is 9.878 g/mol.

7 0

3 years ago

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