Answer:
Option A is correct. The system is at equilibrium
Explanation:
Step 1: Data given
Kc at 1300 K = 5.00
Initial concentration of SO2 = 1.20 M
Initial concentration of O2 = 0.45 M
The concentration of SO3 = 1.80 M
When Q=K, the system is at equilibrium and there is no shift to either the left or the right.
When Q<K, there are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.
When Q>K, there are more products than reactants. To decrease the amount of products, the reaction will shift to the left and produce more reactants.
Step 2: The balanced equation
2 SO2(g) + O2(g) ⇌ 2 SO3(g)
Step 3: Calculate Q
Q = [SO3]² / [O2][SO2]²
Q = 1.80²/0.45*1.20²
Q = 5.00
Q = Kc
This means , the system is at equilibrium and there is no shift to either the left or the right.
Option A is correct.