Answer:
0.48 V
Explanation:
Zn(s) ------------> Zn^2+(aq) + 2e. Oxidation half equation (-0.76V)
Co^2+(aq) + 2e-----------> Co(s). Reduction half equation (-0.28)
Zn(s) + Co^2+(aq) -------------> Zn^2+(aq) + Co(s) overall redox equation
Zinc is the anode while cobalt is the cathode.
E°cell= E°cathode - E°anode
E°cell= -0.28-(-0.76)= 0.48 V
Answer: electronic configuration
Explanation:
Explanation:
Volume is the quantity of three-dimensional
<u>Answer:</u> The concentration of hydrogen ion and bromoacetate ion is 0.0132 M and 0.0132 M resepectively and that of bromoacetic acid is 0.0868 M
<u>Explanation:</u>
We are given:
Molarity of bromoacetic acid = 0.100 M
Percent of ionization = 13.2 %
The chemical equation for the ionization of bromoacetic acid follows:

1 mole of bromoacetic acid produces 1 mole of bromoacetate ion and 1 mole of hydrogen ion
Molarity of hydrogen ion = 13.2 % of 0.100 = 
Molarity of bromoacetate ion = molarity of hydrogen ion = 0.0132 M
Molarity of bromoacetic acid = Molarity of solution - Molarity of ionized substance
Molarity of bromoacetic acid = 0.100 - 0.0132 = 0.0868 M
Hence, the concentration of hydrogen ion and bromoacetate ion is 0.0132 M and 0.0132 M resepectively and that of bromoacetic acid is 0.0868 M
Answer:
6 oxygen atoms
Explanation:
Step 1: Given data
Number of dinitrogen monoxide molecules (N₂O): 6
Number of oxygen atoms (O): ?
Step 2: Calculate the appropriate ratio
The ratio of dinitrogen monoxide molecules to oxygen atoms is 1:1.
Step 3: Use the ratio to calculate the number of oxygen atoms
6 molecule N₂O × (1 atom O/1 molecule N₂O): 6 atom O