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choli [55]
3 years ago
11

What is a possible set of quantum numbers for the unpaired electron in the following electron configuration: [Ar] 3d10 4s2 4p5?

a. n=3, ℓ =1, mℓ =−1, ms =+½ b. n=3, ℓ =2, mℓ =−1, ms =−½ c. n=4, ℓ =2, mℓ =−2, ms =+½ d. n=4, ℓ =0, mℓ = 0, ms =+½ e. n=4, ℓ =1, mℓ =−1, ms =+½
Chemistry
1 answer:
Bogdan [553]3 years ago
6 0

Answer:E

Explanation:

The electron is expected to be in any of the 4p orbitals. For the 4p orbitals

n=4

l=1

ml=-1,0,1

ms=-1/2 or +1/2

All the ml and ms configurations are equiprobable hence the answer.

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Explanation:

First we have to calculate the moles of Na.

\text{Moles of Na}=\frac{\text{Mass of Na}}{\text{Molar mass of Na}}=\frac{41.9g}{23g/mole}=1.82moles

Now we have to calculate the moles of Br_2

{\text{Moles of}Br_2} = \frac{\text{Mass of }Br_2 }{\text{Molar mass of} Br_2} =\frac{30.3g}{160g/mole}=0.189moles

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As, 1 mole of bromine react with = 2 moles of Sodium

So, 0.189 moles of bromine react with = \frac{2}{1}\times 0.189=0.378 moles of Sodium

Thus bromine is the limiting reagent as it limits the formation of product and Na is the excess reagent.

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Now we have to calculate the percent yield of reaction

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