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2 years ago

How do you figure out the problem

Mathematics

1 answer:

zhuklara [117]2 years ago

4 0

Since 7y and 5y has the same variable, add them together.

7y + 5y = 12y

We get 12y, so y has to multiply 12 to get 16. I divided 16 by 12, which got me 1.3333333.

16 divide by 12 = 1.33333333

y = 1.33333333 ( 3 keeps going on )

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PLEASE HELP GEOMETRY

kiruha [24]

Answer:

Hewo! Thanks for the question.

So, we have given a right angle triangle with adjacent side = 16 and let 74° is angle A, We have to find the perpendicular or x.

Let's move straight to the answering process,

According to question,

Tan74° = opp/adj

Tan74° = x/16

x = Tan74°×16

Tan74° is equals to 3.48,

x = 3.48×16

x = 55.8

Hope it helps!<3

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3 years ago

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2 years ago

Consider this system of equations. Which shows the first equation written in slope-intercept form?

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3 years ago

Read 2 more answers

Prove that (sin theta +cos theta) (tan theta + cot theta) = sec theta +cosec theta

denpristay [2]

Answer:

See below

Step-by-step explanation:

$( \sin \theta + \cos \theta)( \tan \theta + \cot \theta) \\ = \sec \theta + \cosec \theta \\ \\ LHS = ( \sin \theta + \cos \theta)( \tan \theta + \cot \theta) \\ \\ = ( \sin \theta + \cos \theta) \bigg( \frac{\sin \theta}{\cos \theta} + \frac{\cos \theta}{\sin \theta} \bigg) \\ \\ = ( \sin \theta + \cos \theta) \bigg( \frac{\sin ^{2} \theta +\cos ^{2} \theta }{\sin \theta \: \cos \theta} \bigg) \\ \\ = ( \sin \theta + \cos \theta) \bigg( \frac{ 1 }{\sin \theta \: \cos \theta} \bigg) \\ \\ = \frac{ \sin \theta + \cos \theta }{\sin \theta \: \cos \theta} \\ \\ = \frac{ \sin \theta }{\sin \theta \: \cos \theta} + \frac{\cos \theta }{\sin \theta \: \cos \theta}\\ \\ = \frac{ 1 }{\cos \theta} + \frac{1 }{\sin \theta} \\ \\ = \sec \theta + \cosec \theta \\ \\ = RHS$

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2 years ago

What is the phrase 3x-6?

jok3333 [9.3K]

3x-6=o
The -6 will then move to the other side and become
3x=6
x=6/3
=2

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3 years ago