First number = x
Second number = x + 2
Third number = x + 4
X + x +2 + x + 4 = 438
Simplify:
3x + 6 = 438
Subtract 3 from both sides
3x = 432
Divide both sides by 3
X = 144
The second number is 144 + 2 = 146
Answer:
Using z score formula:
X = z ∂ + µ
= 157.833
Step-by-step explanation:
Solution:
Mean = µ = 1262
Standard deviation = ∂ = 117
(a) 28th percentile for the number of chocolate chip.
P( z < z) = 28%
= 0.28
P( z<- 0.58) = 0.28
Z = -0.58
By using z score formula:
Z = x - µ /∂
-0.58= x – 117 / 1262
X = (- 0.58)(117) + (1262)
= 1194.14
(b) Middle 97% of bag.
P(-z < z < z) = 97%
= 0.97
P( z < z) – p(z < -z) = 0.97
2p(z < z) -1 = 0.97
2p (z < z) = 1 + 0.97
P(z < z) = 1.97 / 2
= 0.99
P(z < 2.33) = 0.99
Z ± 2.33
By using z score formula:
Z = x - µ / ∂
X = z ∂ + µ
= - 2.33 x 117 + 1262
=989.39
Z = 2.33
X = z ∂ + µ
= 2.33 x 117 + 1262
=1533.61
(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate.
By using standard normal table,
The z dist’n formula:
P(z < z ) = 25%
=0.25
P(z < -0.6745) = 0.25
Z = 0.6745
Using z score formula:
X = z∂ + µ
= - 0.6745 x 117 + 1262
= 1183.0835
First quartile = Q1 =1183.0835
The third quartile is:
P(z<z) = 75%
= 0.75
P(z < 0.6745) = 0.75
Z = 0.6745
Using z score formula:
X = z ∂ + µ
= 0.6745 x 117 + 1262
= 1340.9165
IQR = Q3 – Q1
= 1340.9165 – 1183.0835
= 157.833
Answer:
6y/8+12-12=84-12
6y/8=72
8/6*6y/8=72*8/6
y=96
Step-by-step explanation:
first u get rid of the 12 by subtracting it from both side until u get 6y/8 =72. Then to isolate y u have to multiply the reciprocal of 6/8(8/6) by 6y/8, and u do the same thing to the other side. Then when they cancel out each other y would be left to equal 96.
Answer:
Step-by-step explanation:
Distributive Property: 
Write An Equation:
(5 * x) + (5 * 3)
Solve:
5 * x = 5x
5 * 3 = 15
Rewrite Equation
5x + 15
