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Brilliant_brown [7]
3 years ago
7

HELP DUE TODAY! WILL GIVE 18 PTS!! * Question is in picuture *

Mathematics
1 answer:
gulaghasi [49]3 years ago
6 0

Answer:

7/8

Step-by-step explanation:

you find the common denominator which is 2 so you can divide both by two to get 7/8

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If ABCD is dilated by a factor of 2, the
IrinaVladis [17]

Answer:

I believe its (- 2, 2 )

Step-by-step explanation:

Assuming the dilatation is centred at the origin, then multiply the coordinates of B by the scale factor 2, that is

B(- 1, 1 ) → B'(2(- 1), 2(1) ) → B'(- 2, 2 )

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3 years ago
In the equation y = kx, if x is doubled, what happens to y? doubles triples quadruples unknown
s344n2d4d5 [400]
Correct answer is
<u>doubles</u>



7 0
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Talyn is riding her bike down the street at
EleoNora [17]

Step-by-step explanation:

1 kilometer

thank you very much

4 0
2 years ago
Select all the true statements about the number 3,600−−−−−√.
Paul [167]

Answer:

3,600−−−−−√ is a rational number.I guess

6 0
3 years ago
Read 2 more answers
leonhard wants to place a triangular-based cabinet in the corner of his rectangle-shaped living room. the triangular base has a
Georgia [21]
The answer is x =  \frac{-7+ \sqrt{193} }{4}.

There is very similar question on Brainly, in which dimensions of the living room are given (20 feet, 30 feet).
So, knowing this, we first need to calculate how much 6% of the living room is.
The area of the living room is 600 square feet, since it is rectangle-shaped:
P = a * b = 200 feet * 30 feet = 600 square feet.

6% of 600 square feet is 36 square feet:
600 square feet : 100% = A : 6%
A = 600 * 6 / 100 = 36 square feet

The area of the triangular-based cabinet (A) is A = \frac{a*h}{2}, where a is the base, and h is the height of the triangle.
It is given:
A = 36
a = 2x + 3
h = 3x + 6

Now, let's implement this to the formula A =  \frac{a*h}{2}:
36 =  \frac{(2x+3)(3x+6)}{2}
⇒ 36*2=6 x^{2} +12x+9x+18
72=6 x^{2} +21x+18

Let's both sides divide by 3:
24=2 x^{2} +7x+6
⇒ 2 x^{2} +7x-18=0

This is the quadratic formula (a x^{2} +bx+c=0) for which
x =  \frac{-b+\sqrt{b^{2} -4ac} }{2a} or
<span>x = \frac{-b-\sqrt{b^{2} -4ac} }{2a}.
</span>We will use only <span>x = \frac{-b+\sqrt{b^{2} -4ac} }{2a}, because the length cannot have negative value.</span>


<span>From the equation 2 x^{2} +7x-18=0, we know that
</span>a = 2
b = 7
c = -18

Thus, <span> x = \frac{-7+ \sqrt{193} }{4}:
</span>x= \frac{-b+ \sqrt{ b^{2} -4ac} }{2a} = \frac{-7+ \sqrt{ (7)^{2} -4*2*(-18)} }{2*2} = \frac{-7+ \sqrt{49+144} }{4} = \frac{-7+ \sqrt{193} }{4}

4 0
3 years ago
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