430-18 not in index
p+18=430
This question is not correctly written.
Complete Question
Select all equations that can represent the question: "How many groups of 4/5 are in 1?" A ?⋅1=4/5? Times 1 is equal to 4 fifths B 1⋅4/5=?1 times 4 fifths is equal to ? C 4/5÷1=?4 fifths divided by 1 is equal to ? D ?⋅4/5=1? Times 4 fifths is equal to 1 E 1÷4/5=?1 divided by 4 fifths is equal to ?
Answer:
D ?⋅4/5=1 = ? Times 4 fifths is equal to
E 1÷4/5=? = 1 divided by 4 fifths is equal to
Step-by-step explanation:
How many groups of 4/5 are in 1?
The operation used to solve this is that Division operation.
Hence, we solve it by saying:
1 ÷ 4/5 = ?
= 1× 5/4 = ?
5/4 = ?
Cross Multiply
5 = 4 × ?
? = 5/4
The equations that can represent the question: is
Option D ?⋅4/5=1 = ? Times 4 fifths is equal to
Option E 1÷4/5=? = 1 divided by 4 fifths is equal to
Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:
I think you have the question incomplete, and that this is the complete question
sin^4a + cos^4a = 1 - 2sin^2a.cos^2a
To do this, we can start my mirroring the equation.
x² + y² = (x + y)² - 2xy,
This helps us break down the power from 4 to 2, so that we have
(sin²a)² + (cos²a)² = (sin²a + cos²a) ² - 2(sin²a) (cos²a)
Recall from identity that
Sin²Φ + cos²Φ = 1, so therefore
(sin²a)² + (cos²a)² = 1² - 2(sin²a) (cos²a)
On expanding the power and the brackets, we find that we have the equation proved.
sin^4a + cos^4a = 1 - 2sin^2a.cos^2a
Answer:
3/11
Step-by-step explanation:
given that a cell phone company has three different production sites
Site name 1 2 3 Total
Production 60% 30% 10% 100%
Recalled 5% 7% 9%
Prob for recall 0.003 0.021 0.009 0.033
Total probability for recall = 0.033
Prob for recall and came from site 3 = 0.009
So required probability
= If a randomly selected cell phone has been recalled, what is the probability that it came from Site 3
=
