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goldfiish [28.3K]
2 years ago
8

Find the minimum or maximum of the function. Describe the domain/range in interval notation y=6x^2-1

Mathematics
1 answer:
Margarita [4]2 years ago
7 0

max is at vertex

in form y=ax^2+bx+c

the x value of the vertex is \frac{-b}{2a}

given, y=6x^2-1

a=6, b=0

the x value of the vertex is -0/(2*6)=0

the y value is y=6(0)^2-1=0-1=-1

so vertex is at (0,-1)

since the value of a is positive, the parabola opens up and the vertex is a minimum value of the function

therefore that value is the smallest value the function can be



domain=numbesr you can use for x

range=numbesr you get out of inputting the domain


domain=all real numbers

range is {y | y≥-1} since y=-1 is the minimum

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