Find the minimum or maximum of the function. Describe the domain/range in interval notation y=6x^2-1
1 answer:
max is at vertex
in form
the x value of the vertex is
given,
a=6, b=0
the x value of the vertex is -0/(2*6)=0
the y value is
so vertex is at (0,-1)
since the value of a is positive, the parabola opens up and the vertex is a minimum value of the function
therefore that value is the smallest value the function can be
domain=numbesr you can use for x
range=numbesr you get out of inputting the domain
domain=all real numbers
range is {y | y≥-1} since y=-1 is the minimum
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The graph of the function f(x)=3(2)^x -4 passes through the points (0,-1), (1,2), (2,8) and (3,20)
<h3>How to determine the graph of the function?</h3>The equation of the function is given as:
f(x)=3(2)^x -4
Set x = 0, 1, 2 and 3
f(0)=3(2)^0 -4 = -1
f(1) = 3(2)^(1) - 4 = 2
f(2) = 3(2)^(2) - 4 = 8
f(3) = 3(2)^(3) - 4 = 20
This means that the graph of the function f(x)=3(2)^x -4 passes through the points (0,-1), (1,2), (2,8) and (3,20)
See attachment for the graph of the function
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