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Ne4ueva [31]
3 years ago
8

Which quadrant of the coordinate plane would you use to graph time and distance?

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
8 0

Answer:

quadrant 1

Step-by-step explanation:

Katena32 [7]3 years ago
3 0

Answer:

Quadrant I

Of the coordinate plane would I use to graph time and distance.

Step-by-step explanation:

For plotting any graph be require two axes

x-axis

y-axis

Here we need to graph time and distance, you can take distance on x-axis and time on y-axis or vice a versa.

As we know distance and time is always positive.

In Quadrant I only both the coordinates are positive

i.e X coordinate positive and Y coordinate positive

i.e distance positive and time positive

Therefore we will use Quadrant I to graph time and distance.

In Quadrant II - X coordinate is negative and Y coordinate is positive

In Quadrant III - X coordinate is negative and Y coordinate is negative

In Quadrant IV - X coordinate is positive and Y coordinates is negative

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First, we calculate the slope (m) of 6x + 18y = 11

Make y the subject

18y = -6x + 11

Divide by 18

y = -\frac{1}{3}x + \frac{11}{18}

In y = mx + b

m \to slope

So, the slope of y = -\frac{1}{3}x + \frac{11}{18} is:

m = -\frac 13

Since, the line is perpendicular to 6x + 18y = 11

The slope of the line is:

m_1 = -\frac{1}{m}

So, we have:

m_1 = -\frac{1}{-1/3}

m_1 = 3

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So, the equation is:

y =m(x - x_1) + y_1

This gives:

y =3(x - 4) -2

y =3x - 12 -2

y =3x - 14

Hence, the linear equation is:

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3 years ago
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Answer:

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3 years ago
Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

P(X\leq3) =0.944444369992\approx 0.94

Hence, the required probability is 0.94

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3 years ago
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