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AnnZ [28]
2 years ago
7

20 POINTS PLEASE ANSWER ASAP What is the equation for the line? Enter your answer in the box.

Mathematics
1 answer:
pogonyaev2 years ago
7 0

Answer: y= -2x - 4

Step-by-step explanation:

This is a straight line, so it can be expressed by y = mx + c.

Here c is y-intercept, which means where line cuts the y-axis. We can see from the graph that the line cuts the y-axis at -4.

So, c = -4.

m is slope.

Use slope formula to find m.

m = ( -4 - 0 ) / ( 0 -(-2))

m = -4 / 2

m = -2

Now put values into this equation

y = mx + c

y = -2x - 4

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100 POINTS I NEED HELP ASAP <br><br> If h(x) = |2x-4| , find (h-7)
nikitadnepr [17]

Answer:

The answer is 18.

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2 years ago
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3 years ago
A particle, initially at rest, moves along the x-axis such that its acceleration at time t &gt; 0 is given by a(t) = 6cos(t). At
Rom4ik [11]

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v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t

Then the position function is

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3 0
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Write an equation for this
Cerrena [4.2K]

Answer:

Y=(-x/2)-3

Step-by-step explanation:

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(0,-3) and (-4,-1)

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8 0
3 years ago
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